标签:ext 整数 toc 消息 进一步 代码 class img i++
1.请编写一个程序将一个整数转换为汉字读法字符串。
比如“1123”转换为“一千一百二十三”。
更进一步,能否将数字表示的金额改为“汉字表达?
代码:
import java.util.Scanner; public class Dongnao { public static void main(String[] args) { // TODO Auto-generated method stub Scanner in=new Scanner(System.in); System.out.println("输入一个数:"); double a; a=in.nextDouble(); System.out.println(digitUppercase(a)); } public static String digitUppercase(double n) { String fraction[] = { "角", "分"}; String digit[] = { "零", "壹", "贰", "叁", "肆", "伍", "陆", "柒", "捌", "玖"}; String unit[][] = { { "元", "万", "亿"}, { "", "拾", "佰", "仟"}}; String head = n < 0 ? "负" : ""; n = Math.abs(n); String s = ""; for (int i = 0; i < fraction.length; i++) { s += (digit[(int) (Math.floor(n * 10 * Math.pow(10, i)) % 10)] + fraction[i]).replaceAll("(零.)+", ""); } if (s.length() < 1) { s = "整"; } int integerPart = (int) Math.floor(n); for (int i = 0; i < unit[0].length && integerPart > 0; i++) { String p = ""; for (int j = 0; j < unit[1].length && n > 0; j++) { p = digit[integerPart % 10] + unit[1][j] + p; integerPart = integerPart / 10; } s = p.replaceAll("(零.)*零$", "").replaceAll("^$", "零") + unit[0][i] + s; } return head + s.replaceAll("(零.)*零元", "元").replaceFirst("(零.)+", "").replaceAll("(零.)+", "零").replaceAll("^整$", "零元整"); } }
2.
前面几讲介绍过JDK所提供的BigInteger能完成大数计算,如果不用它,直接使用数组表达大数,你能实现相同的功能吗? 要求: (1)用你的大数类实现加和减两个功能 (2)阅读BigInteger类源码,弄清楚它是使用什么算法实现加减乘除四种运算的? (3)通过互联网查找大数运算的相关资料,给你的大数类添加乘、除、求阶乘等其它功能。
import java.util.Scanner; public class Dongnao { public static void main(String[] args) { String s1,s2; Scanner in=new Scanner(System.in); System.out.println("输入第一个大数:"); s1=in.next(); System.out.println("输入第二个大数:"); s2=in.next(); System.out.println(add(s1,s2)); System.out.println(sub(s1,s2)); } private static String add(String a, String b) { System.out.print("加法:" + a+ "+" + b + "="); char[] aa = new StringBuffer(a).reverse().toString().toCharArray(); char[] bb = new StringBuffer(b).reverse().toString().toCharArray(); int aLen = aa.length; int bLen = bb.length; int len = aLen > bLen ? aLen : bLen; int[] result = new int[len + 1]; for (int i = 0; i < len + 1; ++i) { int aint = i < aLen ? aa[i] - ‘0‘ : 0; int bint = i < bLen ? bb[i] - ‘0‘ : 0; result[i] = aint + bint; } for(int i=0;i<result.length-1;++i){ if(result[i]>=10){ result[i+1] += result[i]/10; result[i] %= 10; } } boolean flag = true; StringBuffer sb = new StringBuffer(len); for(int i=len;i>=0;--i){ if(result[i]==0&&flag){ continue; } else{ flag=false; } sb.append(result[i]); } return sb.toString(); } public static String sub(String f, String s) { System.out.print("减法:" + f + "-" + s + "="); char[] a = new StringBuffer(f).reverse().toString().toCharArray(); char[] b = new StringBuffer(s).reverse().toString().toCharArray(); int lenA = a.length; int lenB = b.length; int len = lenA > lenB ? lenA : lenB; int[] result = new int[len]; char sign = ‘+‘; if (lenA < lenB) { sign = ‘-‘; } else if (lenA == lenB) { int i = lenA - 1; while (i > 0 && a[i] == b[i]) { i--; } if (a[i] < b[i]) { sign = ‘-‘; } } for (int i = 0; i < len; i++) { int aint = i < lenA ? (a[i] - ‘0‘) : 0; int bint = i < lenB ? (b[i] - ‘0‘) : 0; if (sign == ‘+‘) { result[i] = aint - bint; } else { result[i] = bint - aint; } } for (int i = 0; i < result.length - 1; i++) { if (result[i] < 0) { result[i + 1] -= 1; result[i] += 10; } } StringBuffer sb = new StringBuffer(); if (sign == ‘-‘) { sb.append(‘-‘); } boolean flag = true; for (int i = len - 1; i >= 0; i--) { if (result[i] == 0 && flag) { continue; } else { flag = false; } sb.append(result[i]); } if (sb.toString().equals("")) { sb.append("0"); } System.out.println(sb.toString()); return sb.toString(); } }
3.
随机生成10个数,填充一个数组,然后用消息框显示数组内容,接着计算数组元素的和,将结果也显示在消息框中。
import javax.swing.JOptionPane; public class Dongnao { public static void main(String[] args) { // TODO Auto-generated method stub int a[],sum=0; a=new int[10]; String output=new String(); for(int i=0;i<a.length;i++) { a[i]=(int)(Math.random()*100); } output+="a[10]={"; for(int i=0;i<a.length;i++) { output+=a[i]+" "; } output+="}"; for(int i=0;i<a.length;i++) { sum+=a[i]; } output+="\nsum:"+sum; JOptionPane.showMessageDialog(null, output,"结果", JOptionPane.PLAIN_MESSAGE); } }
源代码:
标签:ext 整数 toc 消息 进一步 代码 class img i++
原文地址:http://www.cnblogs.com/zhangbaohai/p/6036579.html