标签:imp -- under stat instant pac ring max merge
https://leetcode.com/problems/create-maximum-number/
这道题目太难了,花了我很多时间。最后还是参考了别人的方法。还少加了个greater方法。很难。
package com.company; import java.util.*; // https://discuss.leetcode.com/topic/32272/share-my-greedy-solution/2 class Solution { public int[] maxNumber(int[] nums1, int[] nums2, int k) { int[] ret = new int[k]; if (nums1.length + nums2.length < k) { return ret; } for (int i=Math.max(0, k-nums2.length); i<=k && i<= nums1.length; i++) { int[] tmp = merge(maxArr(nums1, i), maxArr(nums2, k-i)); if (greater(tmp, 0, ret, 0)) { ret = tmp; } } return ret; } // 必须要有greater函数 boolean greater(int[] nums1, int i, int[] nums2, int j) { while (i < nums1.length && j < nums2.length && nums1[i] == nums2[j]) { i++; j++; } return j == nums2.length || (i < nums1.length && nums1[i] > nums2[j]); } int[] merge(int[] nums1, int[] nums2) { int[] ret = new int[nums1.length + nums2.length]; int t1 = 0; int t2 = 0; for (int i=0; i<ret.length; i++) { if (greater(nums1, t1, nums2, t2)) { ret[i] = nums1[t1++]; } else { ret[i] = nums2[t2++]; } } return ret; } int[] maxArr(int[] nums, int k) { int[] ret = new int[k]; int j = 0; int len = nums.length; for (int i=0; i<len; i++) { while (j>0 && j+len-i>k && ret[j-1] < nums[i]) { j--; } if (j < k) { ret[j] = nums[i]; j++; } } return ret; } } public class Main { public static void main(String[] args) throws InterruptedException { System.out.println("Hello!"); Solution solution = new Solution(); // Your Codec object will be instantiated and called as such: int[] nums1 = {6, 7}; int[] nums2 = {6, 0, 4}; int[] ret = solution.maxNumber(nums1, nums2, 5); for (int i=0; i<ret.length; i++) { System.out.printf("ret:%d\n", ret[i]); } System.out.println(); } }
标签:imp -- under stat instant pac ring max merge
原文地址:http://www.cnblogs.com/charlesblc/p/6036916.html