标签:dia define cstring pre sort efi std stream acm
http://acm.xidian.edu.cn/problem.php?id=1161
列方程推一下,其中某一个村庄假设不动,其他n-1个,最后转化成求绝对值最小问题。
#include<iostream> #include<cstring> #include<cstdio> #include<algorithm> #include<cmath> #define LL long long using namespace std; LL a[1000005] = {0}; int n; int main() { while(~scanf("%d",&n) && n > 0) { LL sum1 = 0,sum2 = 0; for(int i = 1;i <= n;i++) { scanf("%lld",&a[i]); sum1 += a[i]; } for(int i = 1;i <= n;i++) { LL t; scanf("%lld",&t); sum2 += t; a[i] = a[i-1]+t-a[i]; } if(sum1 != sum2) { printf("No way\n"); continue; } sort(a,a+n); LL t = a[n/2],ans = 0; for(int i = 0;i < n;i++) ans += abs(t-a[i]); printf("%lld\n",ans); } return 0; }
标签:dia define cstring pre sort efi std stream acm
原文地址:http://www.cnblogs.com/zhurb/p/6041298.html