标签:efi main 迷宫问题 printf tmp return print false lib
一个10*10的迷宫,每一个格子里面存0或者1,0代表可以走,1代表障碍。
输入值:起始坐标
输出值:能否达到设定的目标坐标点(Bool型变量,1或者0)
1 #include <stdio.h> 2 #include <stdlib.h> 3 4 #define EX 2 5 #define EY 2 6 bool findpath = false; 7 int DX[4]={-1,1,0,0}; 8 int DY[4]={0,0,-1,1}; 9 int maze[10][10]={{0,0,0,1,1,1,1,1,1,1},{1,0,1,1,1,1,1,1,1,1},{1,0,0,1,1,1,1,1,1,1},{1,1,1,1,1,1,1,1,1,1},{0,1,1,0,1,0,0,1,1},{0,1,1,0,1,0,0,1,1},{0,1,1,0,1,0,0,1,1},{0,1,1,0,1,0,0,1,1},{0,1,1,0,1,0,0,1,1},{0,0,0,0,0,0,0,1,1,1}}; 10 int count; 11 12 void DFS(int x,int y){ 13 if(x==EX&&y==EY){ 14 findpath = true; 15 count++; 16 return; 17 } 18 for(int i=0;i<4;i++){ 19 int NX = x +DX[i]; 20 int NY = y +DY[i]; 21 if(NX<=10&&NY<=10&&NX>=0&&NY>=0&&maze[NX][NY]==0) 22 { 23 int tmp = maze[NX][NY]; 24 maze[NX][NY] = 2; 25 DFS(NX,NY); 26 maze[NX][NY] = tmp; 27 } 28 29 } 30 } 31 32 int main(){ 33 34 DFS(0,0); 35 printf("%d\n",findpath); 36 printf("%d\n",count); 37 system("pause"); 38 }
标签:efi main 迷宫问题 printf tmp return print false lib
原文地址:http://www.cnblogs.com/linux0537/p/6070325.html