码迷,mamicode.com
首页 > 其他好文 > 详细

Leetcode 160. Intersection of two linked lists

时间:2016-11-17 09:57:44      阅读:132      评论:0      收藏:0      [点我收藏+]

标签:and   相同   tin   next   nod   style   section   intersect   sts   

 1 class Solution(object):
 2     def getIntersectionNode(self, headA, headB):
 3         """
 4         :type head1, head1: ListNode
 5         :rtype: ListNode
 6         """
 7         
 8         n = self.getLength(headA)
 9         m = self.getLength(headB)
10         
11         if n < m:
12             return self.getIntersectionNode(headB, headA)
13         
14         for i in range(n-m):
15             headA = headA.next
16         
17         while headA and headB:
18             if id(headA) == id(headB):
19                 return headA
20             headA = headA.next
21             headB = headB.next
22         return None
23     
24     def getLength(self, head):
25         n = 0
26         while head:
27             head = head.next
28             n += 1
29         return n

Keys:

1. 总是操作长度较短的那个list

2. 用L18判断两个node是不是相同

Leetcode 160. Intersection of two linked lists

标签:and   相同   tin   next   nod   style   section   intersect   sts   

原文地址:http://www.cnblogs.com/lettuan/p/6072409.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!