标签:sys code print return log out element i++ length
Given an array of size n, find the majority element. The majority element is the element that appears more than ? n/2 ?
times.
You may assume that the array is non-empty and the majority element always exist in the array.
package cn.magicdu; import java.util.HashMap; import java.util.Map; public class _169_Majority_Element { /*public static void main(String[] args) { _169_Majority_Element e=new _169_Majority_Element(); int arr[]={2,2,2,3,4,5,5,6,6,6,6,6,6,6,6}; System.out.println(e.majorityElement(arr)); }*/ public int majorityElement(int[] nums) { Map<Integer,Integer> map=new HashMap<>(); int size=nums.length; for(int i=0;i<size;i++){ if(map.containsKey(nums[i])){ map.put(nums[i],map.get(nums[i])+1); }else{ map.put(nums[i],1); } if(map.get(nums[i])+1>size/2){ return nums[i]; } } return 0; } }
每天一道LeetCode--169.Majority Elemen
标签:sys code print return log out element i++ length
原文地址:http://www.cnblogs.com/xiaoduc-org/p/6076906.html