Leetcode-88 Merge Sorted Array

标签：ace   from   addition   ber   san   sort   cti   str   class   

#88.   Merge Sorted Array   

Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.

Note:
You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2. The number of elements initialized in nums1 and nums2 are m and n respectively.

题解：利用好nums1的后半部分空间。

class Solution {
public:
    void merge(vector<int>& nums1, int m, vector<int>& nums2, int n) {
       int k=m+n-1;
       m=m-1;
       n=n-1;
       while(m>=0&&n>=0)
       {
           if(nums1[m]<nums2[n])
           {
               nums1[k--]=nums2[n--];
           }
           else
           {
               nums1[k--]=nums1[m--];
           }
       }
       while(n>=0)
       {
           nums1[k--]=nums2[n--];
       }
    }
};

Leetcode-88 Merge Sorted Array

标签：ace   from   addition   ber   san   sort   cti   str   class   

原文地址：http://www.cnblogs.com/fengxw/p/6085962.html