标签：简单题

原题http://acm.hdu.edu.cn/showproblem.php?pid=4950

Monster

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 566    Accepted Submission(s): 231

5 3 2 2
0 0 0 0

Case #1: NO

#include <stdio.h>
#include <stdlib.h>
#include <malloc.h>
#include <limits.h>
#include <ctype.h>
#include <string.h>
#include <string>
#include <math.h>
#include <algorithm>
#include <iostream>
#include <stack>
#include <queue>
#include <deque>
#include <vector>
#include <set>
#include <map>
using namespace std;

int main()
{
    __int64 cas=1;
    __int64 h,a,b,k;

   while(~scanf("%I64d%I64d%I64d%I64d",&h,&a,&b,&k)){
        if(h==0 && a==0 && b==0 && k==0){
            break;
        }

        if(h <= a){
            printf("Case #%I64d: YES\n",cas++);
            continue;
        }
        if(a <= b){
            printf("Case #%I64d: NO\n",cas++);
            continue;
        }
        if(h-(a-b)*(k-1)-a <= 0){//K回合之内就打败了，不能回血。
            printf("Case #%I64d: YES\n",cas++);
            continue;
        }
        if(h-(a-b)*(k)+b < h){
            printf("Case #%I64d: YES\n",cas++);
            continue;
        }
        else{
            printf("Case #%I64d: NO\n",cas++);
        }
   }

   return 0;
}

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简单题

标签：简单题

原文地址：http://blog.csdn.net/zcr_7/article/details/38587041