标签：rom step otto ace 三角形 ini min using sharp
Given a triangle, find the minimum path sum from top to bottom. Each step you may move to adjacent numbers on the row below.
For example, given the following triangle
[
[2],
[3,4],
[6,5,7],
[4,1,8,3]
]
The minimum path sum from top to bottom is 11 (i.e., 2 + 3 + 5 + 1 = 11).
Note:
Bonus point if you are able to do this using only O(n) extra space, where n is the total number of rows in the triangle.
给定一个三角形，求最小路径。每层只能选一个整数，上一层和下一层的数必须是相邻的。
class Solution {
public:
int minimumTotal(vector<vector<int>>& triangle) {
for (int i = triangle.size() - 2; i >= 0; --i)
{
for (int j = 0; j < triangle[i].size(); ++j)
{
triangle[i][j] += min(triangle[i + 1][j], triangle[i + 1][j + 1]);
}
}
return triangle[0][0];
}
};
标签：rom step otto ace 三角形 ini min using sharp
原文地址：http://www.cnblogs.com/darrelssc/p/6088516.html
