标签:螺旋矩阵
Given an integer n, generate a square matrix filled with elements from 1 to n2 in spiral order.
For example,
Given n = 3,
[ [ 1, 2, 3 ], [ 8, 9, 4 ], [ 7, 6, 5 ] ]
class Solution {
public:
vector<vector<int> > generateMatrix(int n) {
vector<vector<int> > matrix;
if(n < 0)
return matrix;
int **m = new int*[n];
for(int i = 0; i < n; i++)
{
m[i] = new int[n];
memset(m[i], 0, sizeof(int)*n);
}
int currentnum = 1;
int loop = 0;
while(loop < (n+1)/2)
{
int tmp = n - 1 - loop;
for(int i = loop; i <= tmp; i++)
m[loop][i] = currentnum++;
for(int i = loop + 1; i <= tmp; i++)
m[i][tmp] = currentnum++;
for(int i = tmp - 1; i >= loop; i--)
m[tmp][i] = currentnum++;
for(int i = tmp - 1; i >= loop + 1; i--)
m[i][loop] = currentnum++;
loop++;
}
for(int i = 0; i < n; i++)
{
vector<int> tmp;
for(int j = 0; j < n; j++)
tmp.push_back(m[i][j]);
matrix.push_back(tmp);
}
for(int i = 0; i < n; i++)
delete[] m[i];
delete[] m;
return matrix;
}
};
每日算法之四十一:Spiral Matrix II (螺旋矩阵),布布扣,bubuko.com
每日算法之四十一:Spiral Matrix II (螺旋矩阵)
标签:螺旋矩阵
原文地址:http://blog.csdn.net/yapian8/article/details/38590229