标签:map pen include number break apr closed ted tchar
没什么好说的,注意字符串的处理,以及当数字是13的倍数时,只需高位叫法的单词。比如26,是“hel”,而不是“hel tret”。
代码:
#include <iostream> #include <cstdio> #include <algorithm> #include <map> #include <string> #include <string.h> using namespace std; char mars1[13][20]={"tret","jan", "feb", "mar", "apr", "may", "jun", "jly", "aug", "sep", "oct", "nov", "dec"}; char mars2[13][20]={"","tam", "hel", "maa", "huh", "tou", "kes", "hei", "elo", "syy", "lok", "mer", "jou"}; map<char*,int>maps; int main() { int n; char str[20]; int decade,digit; scanf("%d",&n); getchar(); for(int i=0;i<n;i++){ gets(str); if(‘0‘<=str[0]&&str[0]<=‘9‘){ int num=atoi(str); if(num/13 && num%13==0){ //注意整除的情况。。。 printf("%s\n",mars2[num/13]); } else if(num/13){ decade=num/13; digit=num%13; printf("%s %s\n",mars2[decade],mars1[digit]); } else{ printf("%s\n",mars1[num]); } } else{ int len=strlen(str); //如果是一个字符串的话,加上\0顶多4位。不过要注意也要比较下十位数 if(len<5){ digit=-1; for(int i=0;i<13;i++){ if(strcmp(str,mars1[i])==0){ digit=i; break; } } if(digit==-1){ for(int i=1;i<13;i++){ if(strcmp(str,mars2[i])==0){ decade=i; break; } } printf("%d\n",decade*13); } else printf("%d\n",digit); } else{ char tmp[20]; int i; for(i=0;i<len && str[i]!=‘ ‘;i++){ tmp[i]=str[i]; } tmp[i]=‘\0‘; //十位数 for(int k=1;k<13;k++){ if(strcmp(tmp,mars2[k])==0){ decade=k; break; } } i++; int p=0; for(;i<len;i++,p++) tmp[p]=str[i]; tmp[p]=‘\0‘; //个位数 for(int k=0;k<13;k++){ if(strcmp(tmp,mars1[k])==0){ digit=k; break; } } printf("%d\n",decade*13+digit); } } } return 0; }
PAT甲级题解-1100. Mars Numbers (20)-字符串处理
标签:map pen include number break apr closed ted tchar
原文地址:http://www.cnblogs.com/chenxiwenruo/p/6102581.html