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判断两条线段是否相交

时间:2016-11-27 11:49:03      阅读:291      评论:0      收藏:0      [点我收藏+]

标签:tin   修改   out   section   ctp   public   ima   als   blog   

之前一篇文章里写了一种差乘判断方法:http://www.cnblogs.com/hont/p/6105997.html

 

技术分享

 

bool IsIntersection(Vector3 a, Vector3 b, Vector3 c, Vector3 d)
{
    var crossA = Mathf.Sign(Vector3.Cross(d - c, a - c).y);
    var crossB = Mathf.Sign(Vector3.Cross(d - c, b - c).y);

    if (crossA == crossB) return false;

    var crossC = Mathf.Sign(Vector3.Cross(b - a, c - a).y);
    var crossD = Mathf.Sign(Vector3.Cross(b - a, d - a).y);

    if (crossC == crossD) return false;

    return true;
}

 

 

我也找到了另一个封装好的函数,不仅可以判断相交而且能查到是否相交于虚交点,是否平行等等。

原版是java写的,但出处不详

 

以下是我修改的Unity版本:

public static int GetIntersection(Vector3 a, Vector3 b, Vector3 c, Vector3 d, out Vector3 contractPoint)
{
    contractPoint = new Vector3(0, 0);

    if (Mathf.Abs(b.z - a.z) + Mathf.Abs(b.x - a.x) + Mathf.Abs(d.z - c.z)
            + Mathf.Abs(d.x - c.x) == 0)
    {
        if ((c.x - a.x) + (c.z - a.z) == 0)
        {
            //Debug.Log("ABCD是同一个点!");
        }
        else
        {
            //Debug.Log("AB是一个点,CD是一个点,且AC不同!");
        }
        return 0;
    }

    if (Mathf.Abs(b.z - a.z) + Mathf.Abs(b.x - a.x) == 0)
    {
        if ((a.x - d.x) * (c.z - d.z) - (a.z - d.z) * (c.x - d.x) == 0)
        {
            //Debug.Log("A、B是一个点,且在CD线段上!");
        }
        else
        {
            //Debug.Log("A、B是一个点,且不在CD线段上!");
        }
        return 0;
    }
    if (Mathf.Abs(d.z - c.z) + Mathf.Abs(d.x - c.x) == 0)
    {
        if ((d.x - b.x) * (a.z - b.z) - (d.z - b.z) * (a.x - b.x) == 0)
        {
            //Debug.Log("C、D是一个点,且在AB线段上!");
        }
        else
        {
            //Debug.Log("C、D是一个点,且不在AB线段上!");
        }
        return 0;
    }

    if ((b.z - a.z) * (c.x - d.x) - (b.x - a.x) * (c.z - d.z) == 0)
    {
        //Debug.Log("线段平行,无交点!");
        return 0;
    }

    contractPoint.x = ((b.x - a.x) * (c.x - d.x) * (c.z - a.z) -
            c.x * (b.x - a.x) * (c.z - d.z) + a.x * (b.z - a.z) * (c.x - d.x)) /
            ((b.z - a.z) * (c.x - d.x) - (b.x - a.x) * (c.z - d.z));
    contractPoint.z = ((b.z - a.z) * (c.z - d.z) * (c.x - a.x) - c.z
            * (b.z - a.z) * (c.x - d.x) + a.z * (b.x - a.x) * (c.z - d.z))
            / ((b.x - a.x) * (c.z - d.z) - (b.z - a.z) * (c.x - d.x));

    if ((contractPoint.x - a.x) * (contractPoint.x - b.x) <= 0
            && (contractPoint.x - c.x) * (contractPoint.x - d.x) <= 0
            && (contractPoint.z - a.z) * (contractPoint.z - b.z) <= 0
            && (contractPoint.z - c.z) * (contractPoint.z - d.z) <= 0)
    {

        //Debug.Log("线段相交于点(" + contractPoint.x + "," + contractPoint.z + ")!");
        return 1; // ‘相交  
    }
    else
    {
        //Debug.Log("线段相交于虚交点(" + contractPoint.x + "," + contractPoint.z + ")!");
        return -1; // ‘相交但不在线段上  
    }
}

 

判断两条线段是否相交

标签:tin   修改   out   section   ctp   public   ima   als   blog   

原文地址:http://www.cnblogs.com/hont/p/6106043.html

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