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Convert Sorted List to Binary Search Tree
Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST.
算法思路:
与[leetcode]Convert Sorted Array to Binary Search Tree很相似,不过一个是array,一个是list,无本质区别。
三步走:
找中点(快慢指针)
断链表(需要找慢指针的前驱)
分治。
代码如下:
1 public class Solution { 2 public TreeNode sortedListToBST(ListNode head) { 3 if(head == null) return null; 4 if(head.next == null) return new TreeNode(head.val); 5 ListNode hhead = new ListNode(0); 6 hhead.next = head; 7 ListNode fast = hhead, slow= hhead; 8 while(fast != null && fast.next != null){ 9 fast = fast.next.next; 10 slow = slow.next; 11 } 12 TreeNode root = new TreeNode(slow.val); 13 ListNode right = slow.next; 14 ListNode pre = hhead; 15 while(pre != null && pre.next != slow){ 16 pre = pre.next; 17 } 18 pre.next = null; 19 ListNode left = hhead.next; 20 root.left = sortedListToBST(left); 21 root.right = sortedListToBST(right); 22 return root; 23 } 24 }
[leetcode]Convert Sorted List to Binary Search Tree,布布扣,bubuko.com
[leetcode]Convert Sorted List to Binary Search Tree
标签:style blog http color os io for ar
原文地址:http://www.cnblogs.com/huntfor/p/3916168.html