标签:ring each style array bsp nes lower als i++
Given an arbitrary ransom note string and another string containing letters from all the magazines, write a function that will return true if the ransom note can be constructed from the magazines ; otherwise, it will return false. Each letter in the magazine string can only be used once in your ransom note. Note: You may assume that both strings contain only lowercase letters. canConstruct("a", "b") -> false canConstruct("aa", "ab") -> false canConstruct("aa", "aab") -> true
using one array
1 public class Solution { 2 public boolean canConstruct(String ransomNote, String magazine) { 3 int[] mLetters = new int[26]; 4 for (int i=0; i<magazine.length(); i++) { 5 mLetters[magazine.charAt(i) - ‘a‘]++; 6 } 7 for (int j=0; j<ransomNote.length(); j++) { 8 if (mLetters[ransomNote.charAt(j) - ‘a‘]-- == 0) return false; 9 } 10 return true; 11 } 12 }
标签:ring each style array bsp nes lower als i++
原文地址:http://www.cnblogs.com/EdwardLiu/p/6112099.html