标签:des style blog color io for ar 2014
1 package com.lw.leet2; 2 3 /** 4 * @ClassName:Solution 5 * @Description: 6 * Evaluate the value of an arithmetic expression in Reverse Polish Notation. 7 * Valid operators are +, -, *, /. Each operand may be an integer or another expression. 8 * 9 * Some examples: 10 * ["2", "1", "+", "3", "*"] -> ((2 + 1) * 3) -> 9 11 * ["4", "13", "5", "/", "+"] -> (4 + (13 / 5)) -> 6 12 * 13 * @Author LiuWei 14 * @Date 2014年8月16日上午11:31:05 15 * @Mail nashiyue1314@163.com 16 */ 17 public class Solution { 18 19 private boolean isOper(String s){ 20 if(s.equals("+")){ 21 return true; 22 } 23 if(s.equals("-")){ 24 return true; 25 } 26 if(s.equals("*")){ 27 return true; 28 } 29 if(s.equals("/")){ 30 return true; 31 } 32 return false; 33 } 34 35 private String getOperRes(String num1,String num2,String oper){ 36 if(oper.equals("+")){ 37 return Integer.valueOf(num1)+Integer.valueOf(num2)+""; 38 } 39 else if(oper.equals("-")){ 40 return Integer.valueOf(num1)-Integer.valueOf(num2)+""; 41 } 42 else if(oper.equals("*")){ 43 return Integer.valueOf(num1)*Integer.valueOf(num2)+""; 44 } 45 else{ 46 return Integer.valueOf(num1)/Integer.valueOf(num2)+""; 47 } 48 } 49 50 public int evalRPN(String[] tokens) { 51 String[] resArr = new String[tokens.length]; 52 int index =0; 53 for(int i=0;i<tokens.length;i++){ 54 if(isOper(tokens[i])){ 55 String num1 = resArr[index-1]; 56 String num2 = resArr[index-2]; 57 resArr[index-2] = getOperRes(num2, num1, tokens[i]); 58 index--; 59 } 60 else{ 61 resArr[index] = tokens[i]; 62 index ++; 63 } 64 } 65 return Integer.valueOf(resArr[0]); 66 } 67 68 public static void main(String[] args){ 69 Solution s = new Solution(); 70 // String [] tokens = {"4", "13", "5", "/", "+"}; 71 String [] tokens = {"2", "1", "+"}; 72 System.out.println(s.evalRPN(tokens)); 73 } 74 }
LeetCode-Evaluate Reverse Polish Notation[AC源码],布布扣,bubuko.com
LeetCode-Evaluate Reverse Polish Notation[AC源码]
标签:des style blog color io for ar 2014
原文地址:http://www.cnblogs.com/nashiyue/p/3916278.html