标签:ted out position letter which tco more space store
Given two strings s and t which consist of only lowercase letters. String t is generated by random shuffling string s and then add one more letter at a random position. Find the letter that was added in t. Example: Input: s = "abcd" t = "abcde" Output: e Explanation: ‘e‘ is the letter that was added.
O(N)time, O(1) space
1 public class Solution { 2 public char findTheDifference(String s, String t) { 3 // Initialize variables to store sum of ASCII codes for 4 // each string 5 int charCodeS = 0, charCodeT = 0; 6 // Iterate through both strings and char codes 7 for (int i = 0; i < s.length(); ++i) charCodeS += (int)s.charAt(i); 8 for (int i = 0; i < t.length(); ++i) charCodeT += (int)t.charAt(i); 9 // Return the difference between 2 strings as char 10 return (char)(charCodeT - charCodeS); 11 } 12 }
标签:ted out position letter which tco more space store
原文地址:http://www.cnblogs.com/EdwardLiu/p/6116154.html