Increasing Triplet Subsequence

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Given an unsorted array return whether an increasing subsequence of length 3 exists or not in the array.

Formally the function should:

Return true if there exists i, j, k 
such that arr[i] < arr[j] < arr[k] given 0 ≤ i < j < k ≤ n-1 else return false.

Your algorithm should run in O(n) time complexity and O(1) space complexity.

Examples:
Given [1, 2, 3, 4, 5],
return true.

Given [5, 4, 3, 2, 1],
return false.

 1 public class Solution {
 2     public boolean increasingTriplet(int[] nums) {
 3         if (nums == null || nums.length < 3) return false;
 4         
 5         int m1 = Integer.MAX_VALUE, m2 = Integer.MAX_VALUE;
 6         for (int a : nums) {
 7             if (m1 >= a) m1 = a;
 8             else if (m2 >= a) m2 = a;
 9             else return true;
10         }
11         return false;
12     }
13     
14     
15 }

Increasing Triplet Subsequence

标签：com   nbsp   val   let   examples   class   form   else   for   

原文地址：http://www.cnblogs.com/beiyeqingteng/p/6120538.html