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Given an array where elements are sorted in ascending order, convert it to a height balanced BST.
思路:取数组的中点为树的根,前半部分为左子树,后半部分为右子树。
1 class Solution { 2 public: 3 TreeNode *sortedArrayToBST( vector<int> &num ) { 4 return ConvertSubArray( num, 0, (int)num.size()-1 ); 5 } 6 private: 7 TreeNode *ConvertSubArray( vector<int> &num, int start, int end ) { 8 if( start > end ) { return 0; } 9 int middle = ( start + end ) / 2; 10 TreeNode *treeNode = new TreeNode( num[middle] ); 11 treeNode->left = ConvertSubArray( num, start, middle-1 ); 12 treeNode->right = ConvertSubArray( num, middle+1, end ); 13 return treeNode; 14 } 15 };
Convert Sorted Array to Binary Search Tree,布布扣,bubuko.com
Convert Sorted Array to Binary Search Tree
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原文地址:http://www.cnblogs.com/moderate-fish/p/3917562.html