标签:put discuss its substr false ted ring exp pattern
Given a non-empty string check if it can be constructed by taking a substring of it and appending multiple copies of the substring together. You may assume the given string consists of lowercase English letters only and its length will not exceed 10000. Example 1: Input: "abab" Output: True Explanation: It‘s the substring "ab" twice. Example 2: Input: "aba" Output: False Example 3: Input: "abcabcabcabc" Output: True Explanation: It‘s the substring "abc" four times. (And the substring "abcabc" twice.)
这道题应该没法用DP等解,只能brute force 或者 KMP(为深究)
1 public class Solution { 2 public boolean repeatedSubstringPattern(String str) { 3 int len = str.length(); 4 for (int i=len/2; i>0; i--) { 5 if (len%i == 0) { 6 int m = len / i; 7 String subStr = str.substring(0, i); 8 int j = 1; 9 for (; j<m; j++) { 10 if (!subStr.equals(str.substring(j*i, j*i+i))) 11 break; 12 } 13 if (j == m) return true; 14 } 15 } 16 return false; 17 } 18 }
KMP解法未研究,https://discuss.leetcode.com/topic/67590/java-o-n
Leetcode: Repeated Substring Pattern
标签:put discuss its substr false ted ring exp pattern
原文地址:http://www.cnblogs.com/EdwardLiu/p/6168442.html