码迷,mamicode.com
首页 > 其他好文 > 详细

Leetcode: Repeated Substring Pattern

时间:2016-12-13 08:15:42      阅读:187      评论:0      收藏:0      [点我收藏+]

标签:put   discuss   its   substr   false   ted   ring   exp   pattern   

Given a non-empty string check if it can be constructed by taking a substring of it and appending multiple copies of the substring together. You may assume the given string consists of lowercase English letters only and its length will not exceed 10000.

Example 1:
Input: "abab"

Output: True

Explanation: It‘s the substring "ab" twice.
Example 2:
Input: "aba"

Output: False
Example 3:
Input: "abcabcabcabc"

Output: True

Explanation: It‘s the substring "abc" four times. (And the substring "abcabc" twice.)

这道题应该没法用DP等解,只能brute force 或者 KMP(为深究)

 1 public class Solution {
 2     public boolean repeatedSubstringPattern(String str) {
 3         int len = str.length();
 4         for (int i=len/2; i>0; i--) {
 5             if (len%i == 0) {
 6                 int m = len / i;
 7                 String subStr = str.substring(0, i);
 8                 int j = 1;
 9                 for (; j<m; j++) {
10                     if (!subStr.equals(str.substring(j*i, j*i+i))) 
11                         break;
12                 }
13                 if (j == m) return true;
14             }
15         }
16         return false;
17     }
18 }

KMP解法未研究,https://discuss.leetcode.com/topic/67590/java-o-n

Leetcode: Repeated Substring Pattern

标签:put   discuss   its   substr   false   ted   ring   exp   pattern   

原文地址:http://www.cnblogs.com/EdwardLiu/p/6168442.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!