Sudoku

Time Limit: 2000 MS Memory Limit: 65536 KB

64-bit integer IO format: %I64d , %I64u Java class name: Main

Special Judge

Description

Sudoku is a very simple task. A square table with 9 rows and 9 columns is divided to 9 smaller squares 3x3 as shown on the Figure. In some of the cells are written decimal digits from 1 to 9. The other cells are empty. The goal is to fill the empty cells with decimal digits from 1 to 9, one digit per cell, in such way that in each row, in each column and in each marked 3x3 subsquare, all the digits from 1 to 9 to appear. Write a program to solve a given Sudoku-task.
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Input

The input data will start with the number of the test cases. For each test case, 9 lines follow, corresponding to the rows of the table. On each line a string of exactly 9 decimal digits is given, corresponding to the cells in this line. If a cell is empty it is represented by 0.

Output

For each test case your program should print the solution in the same format as the input data. The empty cells have to be filled according to the rules. If solutions is not unique, then the program may print any one of them.

Sample Input

Sample Output

#include<iostream>
#include <string.h>
#include <stdio.h>

using namespace std;

int map[10][10]; //九宫格

bool row[10][10];    //row[i][x]  标记在第i行中数字x是否出现了
bool col[10][10];    //col[j][y]  标记在第j列中数字y是否出现了
bool grid[10][10];   //grid[k][x] 标记在第k个3*3子格中数字z是否出现了

//(这里说明的字母不代表下面程序中的变量)

bool DFS(int x,int y)  ///从左到右  上到下
{
    if(x==10)
        return true;

    bool flag=false;

    if(map[x][y])
    {
        if(y==9)  ///右边界的列
            flag=DFS(x+1,1);
        else
            flag=DFS(x,y+1);

        if(flag)  //回溯
            return true;
        else
            return false;
    }
    else
    {

        int k=3*((x-1)/3)+(y-1)/3+1;

        for(int i=1; i<=9; i++) //枚举数字1~9填空
            if(!row[x][i] && !col[y][i] && !grid[k][i])
            {
                map[x][y]=i;

                row[x][i]=true;
                col[y][i]=true;
                grid[k][i]=true;

                if(y==9)
                    flag=DFS(x+1,1);
                else
                    flag=DFS(x,y+1);

                if(!flag)   //回溯，继续枚举
                {
                    map[x][y]=0;

                    row[x][i]=false;
                    col[y][i]=false;
                    grid[k][i]=false;
                }
                else
                    return true;
            }
    }
    return false;
}

int main()
{
    int t;
    int i,j;
    cin>>t;
    while(t--)
    {

        char MAP[10][10];
        for(i=1; i<=9; i++)
        {
            for(j=1; j<=9; j++)
            {
                //scanf("%c",&map[i][j]);
                cin>>MAP[i][j];
                map[i][j]=MAP[i][j]-‘0‘;
            }

        }
        memset(row,false,sizeof(row));
        memset(col,false,sizeof(col));
        memset(grid,false,sizeof(grid));
        for(int i=1; i<=9; i++)
        {
            for(int j=1; j<=9; j++)
            {
                if(map[i][j])
                {
                    int k=3*((i-1)/3)+(j-1)/3+1;
                    row[i][ map[i][j] ]=true;
                    col[j][ map[i][j] ]=true;
                    grid[k][ map[i][j] ]=true;
                }
            }
        }

        DFS(1,1);

        for(i=1; i<=9; i++)
        {
            for(j=1; j<=9; j++)
               printf("%d",map[i][j]);
               printf("\n");
        }
    }
    return 0;
}

poj 2676 如何填满九宫格,布布扣,bubuko.com

poj 2676 如何填满九宫格

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原文地址：http://www.cnblogs.com/zhangying/p/3918723.html