标签:start 生成 strong operator enter output accept space case
Time Limit: 3000MS | Memory Limit: 30000K | |
Total Submissions: 31882 | Accepted: 8445 |
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Scenario #1:
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Kruskal()
#include<iostream> #include<algorithm> #include<cstdio> #include<cstring> using namespace std; const int maxn = 1005; struct Edge{ int u,v,w; }edge[maxn*maxn/2]; int fa[maxn]; bool cmp(Edge a,Edge b) { return a.w > b.w; } int find(int x) { return fa[x] == x?fa[x]:fa[x] = find(fa[x]); } void Union(int x,int y) { int fx = find(x),fy = find(y); if (fx != fy) fa[fx] = fy; } int main() { int tcase; scanf("%d",&tcase); for (int t = 1;t <= tcase;t++) { int n,m,res = 0x3f3f3f3f; scanf("%d%d",&n,&m); for (int i = 0;i <= n;i++) fa[i] = i; for (int i = 0;i < m;i++) { scanf("%d%d%d",&edge[i].u,&edge[i].v,&edge[i].w); } sort(edge,edge + m,cmp); for (int i = 0; i< m;i++) { Union(edge[i].u,edge[i].v); if (find(1) == find(n)) { res = edge[i].w; break; } } printf("Scenario #%d:\n",t); printf("%d\n",res); if (t != tcase) printf("\n"); } return 0; }
dijkstra()
#include<iostream> #include<cstdio> #include<cstring> #include<queue> using namespace std; const int maxn = 1005; const int INF = 0x3f3f3f3f; struct Edge{ int u,v,w,nxt; bool operator < (const Edge &a)const { return w < a.w; } }edge[maxn*maxn]; int tot = 0,head[maxn],dis[maxn]; bool vis[maxn]; void addedge(int u,int v,int w) { edge[tot] = (Edge){u,v,w,head[u] }; head[u] = tot++; } void dijkstra(int st,int n) { Edge p; priority_queue<Edge>que; memset(dis,0,sizeof(dis)); memset(vis,false,sizeof(vis)); p.v = st; p.w = INF; dis[st] = INF; que.push(p); while (!que.empty()) { p = que.top(); que.pop(); int u = p.v; if (vis[u]) continue; vis[u] = true; for (int i = head[u];~i;i = edge[i].nxt) { int v = edge[i].v,w = edge[i].w; if (dis[v] < min(dis[u],w)) { dis[v] = min(dis[u],w); p.v = v,p.w = dis[v]; que.push(p); } } } } int main() { int tcase; scanf("%d",&tcase); for (int t = 1;t <= tcase;t++) { int n,m,u,v,w; memset(head,-1,sizeof(head)); scanf("%d%d",&n,&m); for (int i = 0;i < m;i++) { scanf("%d%d%d",&u,&v,&w); addedge(u,v,w); addedge(v,u,w); } dijkstra(1,n); printf("Scenario #%d:\n",t); printf("%d\n",dis[n]); if (t != tcase) printf("\n"); } return 0; }
spfa()
#include<iostream> #include<cstdio> #include<cstring> #include<queue> using namespace std; const int maxn = 1005; const int INF = 0x3f3f3f3f; struct Edge{ int u,v,w,nxt; }edge[maxn*maxn]; int tot = 0,head[maxn],dis[maxn]; bool vis[maxn]; void addedge(int u,int v,int w) { edge[tot] = (Edge){u,v,w,head[u] }; head[u] = tot++; } void spfa(int st,int ed) { memset(vis,false,sizeof(vis)); memset(dis,0,sizeof(dis)); queue<int>que; dis[st] = INF; que.push(st); vis[st] = true; while (!que.empty()) { int u = que.front(); que.pop(); vis[u] = false; for (int i = head[u];~i;i = edge[i].nxt) { int v = edge[i].v,w = edge[i].w; if (min(dis[u],w) > dis[v]) { dis[v] = min(dis[u],w); if (!vis[v]) { que.push(v); vis[v] = true; } } } } } int main() { int tcase; scanf("%d",&tcase); for (int t = 1;t <= tcase;t++) { int n,m,u,v,w; memset(head,-1,sizeof(head)); scanf("%d%d",&n,&m); for (int i = 0;i < m;i++) { scanf("%d%d%d",&u,&v,&w); addedge(u,v,w); addedge(v,u,w); } spfa(1,n); printf("Scenario #%d:\n",t); printf("%d\n",dis[n]); if (t != tcase) printf("\n"); } }
POJ 1797 Heavy Transportation(最大生成树/最短路变形)
标签:start 生成 strong operator enter output accept space case
原文地址:http://www.cnblogs.com/zzy19961112/p/6206998.html