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LeetCode 第一题剪彩自己的leetCode之路

时间:2014-08-18 16:20:32      阅读:142      评论:0      收藏:0      [点我收藏+]

标签:leetcode

Reverse Words in a String

 

Given an input string, reverse the string word by word.

For example,
Given s = "the sky is blue",
return "blue is sky the".

click to show clarification.

Clarification:

  • What constitutes a word?
    A sequence of non-space characters constitutes a word.
  • Could the input string contain leading or trailing spaces?
    Yes. However, your reversed string should not contain leading or trailing spaces.
  • How about multiple spaces between two words?
    Reduce them to a single space in the reversed string.

public class Solution {
    public String reverseWords(String s) {
		 // 判断 ""
		if(s.length()==0) return "";
		// 判断" "
		if(s.length()==1 && s.charAt(0)==' ')return "";
		
		int num = 0;
		boolean flag = false;
		// 得到字符串中单词的个数
		for(int i=0; i < s.length(); i++){
			if(s.charAt(i)!=' '){
				flag = true;
			}else{
				if(flag){
					num++;
					flag = false;
				}
			}
		}
		String str[] = new String[num+1];
		int len=0;
		
		// 分离出单词
		String tempStr = "";
		flag  = false;
		for(int i=0; i < s.length(); i++){
			if(s.charAt(i)!=' '){
				tempStr += s.charAt(i);
				flag = true;
			}else{
				if(flag){
					flag = false;
					str[len++] = tempStr;
					tempStr = "";
				}
			}
		}
		str[len] = tempStr;
		
		// 对单词进行组合,在单词之间加上空格
		String resu = "";
		for(int i=str.length-1; i>=0; i--){
			resu+=str[i];
			if(i!=0)
				resu += " ";
		}
		// 判断结果为""的情况
		if(resu.length()==0) return "";
		
		// 去除前导零和后置零
		int count=0;
		while(resu.charAt(count)==' '){
			resu = resu.substring(count+1);
		}
		count = resu.length()-1;
		while(resu.charAt(count)== ' '){
			resu = resu.substring(0, count);
			count--;
		}
		return resu;
	}
}


LeetCode 第一题剪彩自己的leetCode之路,布布扣,bubuko.com

LeetCode 第一题剪彩自己的leetCode之路

标签:leetcode

原文地址:http://blog.csdn.net/q745401990/article/details/38662073

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