标签:.com pre enter ota [1] define ios main pushd
[BZOJ1552][Cerc2007]robotic sort
试题描述
输入
输入共两行,第一行为一个整数N,N表示物品的个数,1<=N<=100000。第二行为N个用空格隔开的正整数,表示N个物品最初排列的编号。
输出
输入示例
6 3 4 5 1 6 2
输出示例
4 6 4 5 6 6
数据规模及约定
见“输入”
题解
暴力用 splay 模拟。。。
#include <iostream> #include <cstdio> #include <cstdlib> #include <cstring> #include <cctype> #include <algorithm> using namespace std; int read() { int x = 0, f = 1; char c = getchar(); while(!isdigit(c)){ if(c == ‘-‘) f = -1; c = getchar(); } while(isdigit(c)){ x = x * 10 + c - ‘0‘; c = getchar(); } return x * f; } #define maxn 100010 int A[maxn], num[maxn], tot[maxn]; struct Node { int siz; bool rev; Node() {} } ns[maxn]; int ToT, fa[maxn], ch[maxn][2]; void maintain(int o) { ns[o].siz = 1; for(int i = 0; i < 2; i++) if(ch[o][i]) ns[o].siz += ns[ch[o][i]].siz; return ; } void build(int& o, int l, int r) { if(l > r) return ; int mid = l + r >> 1; o = A[mid]; build(ch[o][0], l, mid - 1); build(ch[o][1], mid + 1, r); if(ch[o][0]) fa[ch[o][0]] = o; if(ch[o][1]) fa[ch[o][1]] = o; return maintain(o); } void pushdown(int o) { for(int i = 0; i < 2; i++) if(ch[o][i]) ns[ch[o][i]].rev ^= ns[o].rev; if(ns[o].rev) swap(ch[o][0], ch[o][1]), ns[o].rev = 0; return ; } void rotate(int u) { int y = fa[u], z = fa[y], l = 0, r = 1; if(z) ch[z][ch[z][1]==y] = u; if(ch[y][1] == u) swap(l, r); fa[u] = z; fa[y] = u; fa[ch[u][r]] = y; ch[y][l] = ch[u][r]; ch[u][r] = y; maintain(y); maintain(u); return ; } int S[maxn], top; void splay(int u) { int t = u; S[top = 1] = t; while(fa[t]) t = fa[t], S[++top] = t; while(top) pushdown(S[top--]); while(fa[u]) { int y = fa[u], z = fa[y]; if(z) { if(ch[y][0] == u ^ ch[z][0] == y) rotate(u); else rotate(y); } rotate(u); } return ; } int Find(int o, int k) { pushdown(o); if(!o) return 0; int ls = ch[o][0] ? ns[ch[o][0]].siz : 0; if(k == ls + 1) return o; if(k > ls + 1) return Find(ch[o][1], k - ls - 1); return Find(ch[o][0], k); } int split(int u) { if(!u) return splay(1), 1; splay(u); int tmp = ch[u][1]; fa[tmp] = ch[u][1] = 0; return maintain(u), tmp; } int merge(int a, int b) { if(!a) return b; pushdown(a); while(ch[a][1]) a = ch[a][1], pushdown(a); splay(a); ch[a][1] = b; fa[b] = a; return maintain(a), a; } int main() { int n = read(); for(int i = 1; i <= n; i++) num[i] = A[i] = read(); sort(num + 1, num + n + 1); for(int i = 1; i <= n; i++) { A[i] = lower_bound(num + 1, num + n + 1, A[i]) - num; A[i] += tot[A[i]]++; } int tmp; build(tmp, 1, n); for(int i = 1; i <= n; i++) { splay(i); printf("%d%c", (ch[i][0] ? ns[ch[i][0]].siz : 0) + 1, i < n ? ‘ ‘ : ‘\n‘); int lrt = Find(i, i - 1), mrt = i, rrt; split(lrt); rrt = split(mrt); ns[mrt].rev ^= 1; mrt = merge(lrt, mrt); merge(mrt, rrt); } return 0; }
[BZOJ1552][Cerc2007]robotic sort
标签:.com pre enter ota [1] define ios main pushd
原文地址:http://www.cnblogs.com/xiao-ju-ruo-xjr/p/6257580.html