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There is a plethora of classification algorithms available to people who have a bit of coding experience and a set of data. A common machine learning method is the random forest, which is a good place to start.
This is a use case in R of the randomForest package used on a data set fromUCI‘s Machine Learning Data Repository.
If someone gave you thousands of rows of data with dozens of columns about mushrooms, could you identify which characteristics make a mushroom edible or poisonous? How much would you trust your model? Would it be enough for you to make a decision on whether or not to eat a mushroom you find? (That‘s a bad decision roughly 100% of the time).
The randomForest package does all of the heavy lifting behind the scenes. While this "magic" is incredibly nice for the end user, it‘s important to understand what it is you‘re doing. Keep this in mind for absolutely any package you use in R or any other language.
"To know how to run these programs is impressive, but to truly understand how and why they work is what makes you an expert!" -Haley Stoltzman (my wife is a genius)
Here is an article which explains things in layman‘s terms - A Gentle Introduction to Random Forests, Ensembles, and Performance Metrics in a Commercial System.
I created a function to grab and clean up the data. This happened to be a very manual process so I borrowed a lot of the code from others. Later on, I found that the data set had already been cleaned up by someone else and presented as a .csv file, but I decided to use my function anyway.
source(‘helper_functions.R‘)
library(randomForest)
library(e1071)
library(caret)
library(ggplot2)
set.seed(123)I brought the data in as a dataframe, the first column is "Edible" which could be labeled "Class" as this is what we‘re looking for in the classification. We‘ll find only two values here, "Edible" and "Poisonous" (keep in mind that more than two values are easily handled by random forest).
I printed the first few rows and the output shows us there are 23 columns (including "Edible"). I am not a mushroom expert but most of this data makes sense to try and utilize.
#Import Data via Custom Function
data = fetchAndCleanData()
head(data)## Edible CapShape CapSurface CapColor Bruises Odor GillAttachment
## 1 Poisonous Convex Smooth Brown True Pungent Free
## 2 Edible Convex Smooth Yellow True Almond Free
## 3 Edible Bell Smooth White True Anise Free
## 4 Poisonous Convex Scaly White True Pungent Free
## 5 Edible Convex Smooth Gray False None Free
## 6 Edible Convex Scaly Yellow True Almond Free
## GillSpacing GillSize GillColor StalkShape StalkRoot
## 1 Close Narrow Black Enlarging Equal
## 2 Close Broad Black Enlarging Club
## 3 Close Broad Brown Enlarging Club
## 4 Close Narrow Brown Enlarging Equal
## 5 Crowded Broad Black Tapering Equal
## 6 Close Broad Brown Enlarging Club
## StalkSurfaceAboveRing StalkSurfaceBelowRing StalkColorAboveRing
## 1 Smooth Smooth White
## 2 Smooth Smooth White
## 3 Smooth Smooth White
## 4 Smooth Smooth White
## 5 Smooth Smooth White
## 6 Smooth Smooth White
## StalkColorBelowRing VeilType VeilColor RingNumber RingType
## 1 White Partial White One Pendant
## 2 White Partial White One Pendant
## 3 White Partial White One Pendant
## 4 White Partial White One Pendant
## 5 White Partial White One Evanescent
## 6 White Partial White One Pendant
## SporePrintColor Population Habitat
## 1 Black Scattered Urban
## 2 Brown Numerous Grasses
## 3 Brown Numerous Meadows
## 4 Black Scattered Urban
## 5 Brown Abundnant Grasses
## 6 Black Numerous Grasses
It‘s important to know that R‘s random forest package cannot use rows with missing data. Using the summary() function can help to identify issues. This data doesn‘t have missing information.
summary(data) #no missing data appears## Edible CapShape CapSurface CapColor
## Edible :4208 Convex :3656 Scaly :3244 Brown :2284
## Poisonous:3916 Flat :3152 Smooth :2556 Gray :1840
## Knobbed: 828 Fibrous:2320 Red :1500
## Bell : 452 Grooves: 4 Yellow :1072
## Sunken : 32 f : 0 White :1040
## Conical: 4 g : 0 Buff : 168
## (Other): 0 (Other): 0 (Other): 220
## Bruises Odor GillAttachment GillSpacing
## f : 0 None :3528 a : 0 c : 0
## t : 0 Foul :2160 f : 0 w : 0
## True :3376 Fishy : 576 Attached : 210 Close :6812
## False:4748 Spicy : 576 Descending: 0 Crowded:1312
## Almond : 400 Free :7914 Distant: 0
## Anise : 400 Notched : 0
## (Other): 484
## GillSize GillColor StalkShape StalkRoot
## b : 0 Buff :1728 e : 0 Bulbous:3776
## n : 0 Pink :1492 t : 0 Missing:2480
## Broad :5612 White :1202 Enlarging:3516 Equal :1120
## Narrow:2512 Brown :1048 Tapering :4608 Club : 556
## Gray : 752 Rooted : 192
## Chocolate: 732 ? : 0
## (Other) :1170 (Other): 0
## StalkSurfaceAboveRing StalkSurfaceBelowRing StalkColorAboveRing
## Smooth :5176 Smooth :4936 White :4464
## Silky :2372 Silky :2304 Pink :1872
## Fibrous: 552 Fibrous: 600 Gray : 576
## Scaly : 24 Scaly : 284 Brown : 448
## f : 0 f : 0 Buff : 432
## k : 0 k : 0 Orange : 192
## (Other): 0 (Other): 0 (Other): 140
## StalkColorBelowRing VeilType VeilColor RingNumber
## White :4384 p : 0 White :7924 n : 0
## Pink :1872 Partial :8124 Brown : 96 o : 0
## Gray : 576 Universal: 0 Orange : 96 t : 0
## Brown : 512 Yellow : 8 None: 36
## Buff : 432 n : 0 One :7488
## Orange : 192 o : 0 Two : 600
## (Other): 156 (Other): 0
## RingType SporePrintColor Population Habitat
## Pendant :3968 White :2388 Several :4040 Woods :3148
## Evanescent:2776 Brown :1968 Solitary :1712 Grasses:2148
## Large :1296 Black :1872 Scattered:1248 Paths :1144
## Flaring : 48 Chocolate:1632 Numerous : 400 Leaves : 832
## None : 36 Green : 72 Abundnant: 384 Urban : 368
## e : 0 Buff : 48 Clustered: 340 Meadows: 292
## (Other) : 0 (Other) : 144 (Other) : 0 (Other): 192
I want to explore the data before fitting a model to get an idea of what to expect. I am plotting a variable on two axes and using colors to see the relationship as to whether or not the mushroom is edible or poisonous.
In these plots, edible is shown as green and poisonous is shown as red. I‘m looking for spots where there exists an overwhelming majority of one color.
A comparison of "CapSurface" to "CapShape" shows us:
p = ggplot(data,aes(x=CapShape,
y=CapSurface,
color=Edible))
p + geom_jitter(alpha=0.3) +
scale_color_manual(breaks = c(‘Edible‘,‘Poisonous‘),
values=c(‘darkgreen‘,‘red‘))A comparison of "StalkColorBelowRing" to "StalkColorAboveRing" shows us:
p = ggplot(data,aes(x=StalkColorBelowRing,
y=StalkColorAboveRing,
color=Edible))
p + geom_jitter(alpha=0.3) +
scale_color_manual(breaks = c(‘Edible‘,‘Poisonous‘),
values=c(‘darkgreen‘,‘red‘))A comparison of "Odor" to "SporePrintColor" shows us:
p = ggplot(data,aes(x=Odor,
y=SporePrintColor,
color=Edible))
p + geom_jitter(alpha=0.3) +
scale_color_manual(breaks = c(‘Edible‘,‘Poisonous‘),
values=c(‘darkgreen‘,‘red‘))Due to how strong those variables looked, I decided to plot them strictly as edible or poisonous and found:
p = ggplot(data,aes(x=Edible,
y=Odor,
color = Edible))
p + geom_jitter(alpha=0.2) +
scale_color_manual(breaks = c(‘Edible‘,‘Poisonous‘),
values=c(‘darkgreen‘,‘red‘))p = ggplot(data,aes(x=Edible,
y=SporePrintColor,
color = Edible))
p + geom_jitter(alpha=0.2) +
scale_color_manual(breaks = c(‘Edible‘,‘Poisonous‘),
values=c(‘darkgreen‘,‘red‘))Before fitting a model it‘s important to split data into different parts - train and test data. There‘s no perfect way to know exactly how much data you should use to train your model. In this example I split 5% as training and 95% as testing. However, this is not typical, most of what I see is usually around 60%/40% or 70%/30% for test/train split.
If you choose too large of a training set you run the risk of overfitting your model. Overfitting is a classic mistake people make when first entering the field of machine learning. I won‘t go into the details but there are classes dedicated to this subject. Wikipedia Article
Initially, I ran this at higher levels of training data and it had perfect prediction with zero false positives or negatives. That‘s not as fun to look at as an example so I scaled down the training data which created more bad predictions.
#Create data for training
sample.ind = sample(2,
nrow(data),
replace = T,
prob = c(0.05,0.95))
data.dev = data[sample.ind==1,]
data.val = data[sample.ind==2,]I wanted to know the split of edible to poisonous mushrooms in the data set and compare it to the training and test data. The random sample appears to have created roughly the same ratio of edible to poisonous upon creating train and test data.
Edible % / Poisonous % :
# Original Data
table(data$Edible)/nrow(data)
## Edible Poisonous
## 0.5179714 0.4820286# Training Data
table(data.dev$Edible)/nrow(data.dev)
## Edible Poisonous
## 0.4962779 0.5037221# Testing Data
table(data.val$Edible)/nrow(data.val)
## Edible Poisonous
## 0.5191037 0.4808963
I finally fit the random forest model to the training data. Plotting the model shows us that after about 20 trees, not much changes in terms of error. It fluctuates a bit but not to a large degree.
#Fit Random Forest Model
rf = randomForest(Edible ~ .,
ntree = 100,
data = data.dev)
plot(rf)Printing the model shows the number of variables tried at each split to be 4 and an OOB estimate of error rate 0.25%. The training model fit the training data almost perfectly. There was only one mushroom which was classified incorrectly. The model would have predicted 1 to be poisonous and it would have turned out to be edible. If we consider edible to be "positive" this means we would have had 1 false negative.
print(rf)
## Call:
## randomForest(formula = Edible ~ ., data = data.dev, ntree = 100)
## Type of random forest: classification
## Number of trees: 100
## No. of variables tried at each split: 4
##
## OOB estimate of error rate: 0.25%
## Confusion matrix:
## Edible Poisonous class.error
## Edible 200 0 0.000000000
## Poisonous 1 202 0.004926108It‘s always important to look at what is shown in terms of variable importance. This plot indicates what variables had the greatest impact in the classification model.
I limited it to 10 for the plot.
# Variable Importance
varImpPlot(rf,
sort = T,
n.var=10,
main="Top 10 - Variable Importance")Odor is by far the most important variable in terms of "Mean Decreasing Gini" - a similar term for information gain in this example. The rest of the results are listed below. It‘s interesting to notice "Veil Type" created no information gain - so I looked into it in the initial data. The reason is clear - there is only one VeilType, so it doesn‘t offer any differentiation and couldn‘t possibly impact the results.
#Variable Importance
var.imp = data.frame(importance(rf,
type=2))
# make row names as columns
var.imp$Variables = row.names(var.imp)
print(var.imp[order(var.imp$MeanDecreaseGini,decreasing = T),])
## MeanDecreaseGini Variables
## Odor 69.3536782 Odor
## SporePrintColor 27.3837625 SporePrintColor
## GillColor 18.1981987 GillColor
## StalkSurfaceAboveRing 12.3172400 StalkSurfaceAboveRing
## RingType 11.3114967 RingType
## GillSize 11.1085947 GillSize
## Population 7.2591707 Population
## Bruises 7.2212660 Bruises
## CapColor 5.6746095 CapColor
## Habitat 5.4768013 Habitat
## StalkRoot 5.3053036 StalkRoot
## StalkSurfaceBelowRing 4.6080070 StalkSurfaceBelowRing
## GillSpacing 4.1186021 GillSpacing
## StalkShape 2.6858568 StalkShape
## StalkColorBelowRing 2.5570551 StalkColorBelowRing
## RingNumber 2.0463027 RingNumber
## StalkColorAboveRing 1.9823127 StalkColorAboveRing
## CapSurface 1.0200298 CapSurface
## CapShape 0.5779989 CapShape
## VeilColor 0.1522645 VeilColor
## GillAttachment 0.0275000 GillAttachment
## VeilType 0.0000000 VeilTypeI decided to use the model to attempt to predict whether or not a mushroom is edible or poisonous based off of the training data set. It predicted the response variable perfectly - having zero false positives or false negatives.
# Predicting response variable
data.dev$predicted.response = predict(rf , data.dev)
# Create Confusion Matrix
print(
confusionMatrix(data = data.dev$predicted.response,
reference = data.dev$Edible,
positive = ‘Edible‘))
## Confusion Matrix and Statistics
##
## Reference
## Prediction Edible Poisonous
## Edible 200 0
## Poisonous 0 203
##
## Accuracy : 1
## 95% CI : (0.9909, 1)
## No Information Rate : 0.5037
## P-Value [Acc > NIR] : < 2.2e-16
##
## Kappa : 1
## Mcnemar‘s Test P-Value : NA
##
## Sensitivity : 1.0000
## Specificity : 1.0000
## Pos Pred Value : 1.0000
## Neg Pred Value : 1.0000
## Prevalence : 0.4963
## Detection Rate : 0.4963
## Detection Prevalence : 0.4963
## Balanced Accuracy : 1.0000
##
## ‘Positive‘ Class : EdibleNow it was time to see how the model did with data it had not seen before - making predictions on the test data.
It did a decent job. It had a 99% accuracy with a very narrow confidence interval. It did have 48 false negatives and 8 false positives (which could be deadly if you were actually choosing to eat mushrooms based off of this model).
# Predicting response variable
data.val$predicted.response <- predict(rf ,data.val)
# Create Confusion Matrix
print(
confusionMatrix(data=data.val$predicted.response,
reference=data.val$Edible,
positive=‘Edible‘))
## Confusion Matrix and Statistics
##
## Reference
## Prediction Edible Poisonous
## Edible 3960 8
## Poisonous 48 3705
##
## Accuracy : 0.9927
## 95% CI : (0.9906, 0.9945)
## No Information Rate : 0.5191
## P-Value [Acc > NIR] : < 2.2e-16
##
## Kappa : 0.9855
## Mcnemar‘s Test P-Value : 1.872e-07
##
## Sensitivity : 0.9880
## Specificity : 0.9978
## Pos Pred Value : 0.9980
## Neg Pred Value : 0.9872
## Prevalence : 0.5191
## Detection Rate : 0.5129
## Detection Prevalence : 0.5139
## Balanced Accuracy : 0.9929
##
## ‘Positive‘ Class : EdibleUnfortunately, I have no idea how reliable this data is or how it was captured. There is likely some background information and I would never choose whether or not to eat an unknown mushroom based off of this model (and neither should you).
Code used in this post is on my GitHub
转自：https://stoltzmaniac.com/random-forest-classification-of-mushrooms/
Random Forest Classification of Mushrooms
标签：use case hub tween tab missing ati between comment out
原文地址：http://www.cnblogs.com/payton/p/6279695.html
