标签:下界 define log ace bfs htm return can print
【题目分析】
无源汇上下界可行流。
上下界网络流的问题可以参考这里。↓
http://www.cnblogs.com/kane0526/archive/2013/04/05/3001108.html
【代码】
#include <cstdio>
#include <cstring>
#include <cmath>
#include <cstdlib>
//#include <map>
#include <set>
#include <queue>
#include <string>
#include <iostream>
#include <algorithm>
using namespace std;
#define maxn 205
#define me 50005
#define inf 0x3f3f3f3f
#define F(i,j,k) for (int i=j;i<=k;++i)
#define D(i,j,k) for (int i=j;i>=k;--i)
void Finout()
{
#ifndef ONLINE_JUDGE
freopen("in.txt","r",stdin);
// freopen("out.txt","w",stdout);
#endif
}
int Getint()
{
int x=0,f=1; char ch=getchar();
while (ch<‘0‘||ch>‘9‘) {if (ch==‘-‘) f=-1; ch=getchar();}
while (ch>=‘0‘&&ch<=‘9‘) {x=x*10+ch-‘0‘; ch=getchar();}
return x*f;
}
int h[me<<1],to[me<<1],ne[me<<1],fl[me<<1],en=0,S=0,T=me-1;
int id[me<<1];
void add(int a,int b,int c,int ID)
{
// cout<<"add "<<a<<" "<<b<<" "<<c<<endl;
to[en]=b; ne[en]=h[a]; fl[en]=c; id[en]=ID; h[a]=en++;
to[en]=a; ne[en]=h[b]; fl[en]=0; id[en]=0; h[b]=en++;
}
int map[me];
bool tell()
{
queue <int> q;
memset(map,-1,sizeof map);
map[S]=0;
while (!q.empty()) q.pop();
q.push(S);
while (!q.empty())
{
int x=q.front(); q.pop();
// cout<<"bfs"<<x<<endl;
for (int i=h[x];i>=0;i=ne[i])
{
// cout<<"to "<<to[i]<<endl;
if (map[to[i]]==-1&&fl[i]>0)
{
map[to[i]]=map[x]+1;
q.push(to[i]);
}
}
}
// cout<<"over"<<endl;
if (map[T]!=-1) return true;
return false;
}
int zeng(int k,int r)
{
if (k==T) return r;
int ret=0;
for (int i=h[k];i>=0&&ret<r;i=ne[i])
if (map[to[i]]==map[k]+1&&fl[i]>0)
{
int tmp=zeng(to[i],min(fl[i],r-ret));
ret+=tmp; fl[i]-=tmp; fl[i^1]+=tmp;
}
if (!ret) map[k]=-1;
return ret;
}
int ans[me<<1],n,m,du[me<<1],dn[me<<1];
int main()
{
Finout();
while (scanf("%d%d",&n,&m)!=EOF)
{
memset(h,-1,sizeof h);
memset(ans,0,sizeof ans);
memset(du,0,sizeof du);
memset(dn,0,sizeof dn);
F(i,1,m)
{
int a,b,c,d;
a=Getint();b=Getint();c=Getint();d=Getint();
add(a,b,d-c,i);
du[a]-=c; du[b]+=c; dn[i]+=c;
}
F(i,1,n)
{
if (du[i]) add(S,i,du[i],0);
if (du[i]<0) add(i,T,-du[i],0);
}
int now=0,tmp=0;
while (tell()) while (tmp=zeng(S,inf)) now+=tmp;
int flag=1;
for (int i=h[S];i>=0;i=ne[i])
if (fl[i]>0) flag=0;
if (!flag) printf("NO\n");
else
{
printf("YES\n");
F(i,0,en-1) ans[id[i]]=fl[i^1];
F(i,1,m) printf("%d\n",ans[i]+dn[i]);
}
}
}
标签:下界 define log ace bfs htm return can print
原文地址:http://www.cnblogs.com/Muliphein/p/6287516.html