标签:blog pac iostream 全排列 [] print can string 顶点
题意:给定图,求是带宽最小的结点排列。
分析:结点数最多为8,全排列即可。顶点范围是A~Z。
#pragma comment(linker, "/STACK:102400000, 102400000") #include<cstdio> #include<cstring> #include<cstdlib> #include<cctype> #include<cmath> #include<iostream> #include<sstream> #include<iterator> #include<algorithm> #include<string> #include<vector> #include<set> #include<map> #include<stack> #include<deque> #include<queue> #include<list> #define Min(a, b) ((a < b) ? a : b) #define Max(a, b) ((a < b) ? b : a) typedef long long ll; typedef unsigned long long llu; const int INT_INF = 0x3f3f3f3f; const int INT_M_INF = 0x7f7f7f7f; const ll LL_INF = 0x3f3f3f3f3f3f3f3f; const ll LL_M_INF = 0x7f7f7f7f7f7f7f7f; const int dr[] = {0, 0, -1, 1, -1, -1, 1, 1}; const int dc[] = {-1, 1, 0, 0, -1, 1, -1, 1}; const int MOD = 1e9 + 7; const double pi = acos(-1.0); const double eps = 1e-8; const int MAXN = 100 + 10; const int MAXT = 10000 + 10; using namespace std; char s[MAXN]; set<int> node[30]; vector<int> v; int t[10]; void init(){ for(int i = 0; i < 30; ++i){ node[i].clear(); } v.clear(); memset(t, 0, sizeof t); int len = strlen(s); for(int i = 0; i < len; ++i){ if(s[i] == ‘:‘){ int tmp = s[i - 1] - ‘A‘; while(1){ ++i; if(i == len) break; if(s[i] == ‘;‘) break; node[tmp].insert(s[i] - ‘A‘); node[s[i] - ‘A‘].insert(tmp); } } } } int main(){ while(scanf("%s", s) == 1){ if(s[0] == ‘#‘) return 0; init(); for(int i = 0; i < 30; ++i){ if(node[i].size()){ v.push_back(i); } } int len = v.size(); int ans = INT_M_INF; do{ int tmp = 0; for(int i = 0; i < len; ++i){ for(int j = 0; j < i; ++j){ if(node[v[i]].count(v[j])){ tmp = max(tmp, i - j); } } } if(tmp < ans){ ans = tmp; for(int i = 0; i < len; ++i){ t[i] = v[i]; } } }while(next_permutation(v.begin(), v.end())); for(int i = 0; i < len; ++i){ printf("%c ", ‘A‘ + t[i]); } printf("-> %d\n", ans); } return 0; }
标签:blog pac iostream 全排列 [] print can string 顶点
原文地址:http://www.cnblogs.com/tyty-Somnuspoppy/p/6288041.html