标签:start hand com else sts bsp mini nbsp array
Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand.
(i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2).
Find the minimum element.
You may assume no duplicate exists in the array.
class Solution { public: int findMin(vector<int>& nums) { return dfs(nums,0,nums.size()-1); } int dfs(vector<int>& nums, int start, int end){ if(start==end) return nums[start]; int mid = start + ((end - start) >> 1); if(nums[start] <= nums[mid] && nums[mid] < nums[end]){ //no rotate return nums[start]; } else if(nums[start] <= nums[mid] && nums[mid] > nums[end]){ //rotate in the right return dfs(nums, mid+1,end); } else{ //rorate in the left return dfs(nums, start, mid); } } };
153. Find Minimum in Rotated Sorted Array (Array; Divide-and-Conquer)
标签:start hand com else sts bsp mini nbsp array
原文地址:http://www.cnblogs.com/qionglouyuyu/p/6291529.html