标签:public strong log length imp blog emc main get
读入一个自然数n,计算其各位数字之和,用汉语拼音写出和的每一位数字。
输入格式:每个测试输入包含1个测试用例,即给出自然数n的值。这里保证n小于10100。
输出格式:在一行内输出n的各位数字之和的每一位,拼音数字间有1 空格,但一行中最后一个拼音数字后没有空格。
输入样例:1234567890987654321123456789输出样例:
yi san wu
package com.lwh.agrithmatic.paractice; import java.math.BigInteger; import java.util.ArrayList; import java.util.Scanner; public class Practise2 { public static void main(String[] args) { Scanner scanner=new Scanner(System.in); BigInteger n=scanner.nextBigInteger(); String str=n.toString(); ArrayList<Integer> arrayList=new ArrayList<Integer>(); for(int i=0;i<str.length();i++){ arrayList.add(Integer.parseInt(str.subSequence(i, i+1).toString())); } System.out.println(calResult(arrayList)); } public static String calResult(ArrayList<Integer> arrayList){ String result=""; int sum=0; for(int i=0;i<arrayList.size();i++){ sum+=arrayList.get(i); } String[] strings={"ling","yi","er","san","si","wu","liu","qi","ba","jiu"}; String sum2=Integer.toString(sum); for(int i=0;i<sum2.length();i++){ if(i==sum2.length()-1){ result+=(strings[Integer.parseInt(sum2.subSequence(i, i+1).toString())]); }else{ result+=(strings[Integer.parseInt(sum2.subSequence(i, i+1).toString())]+" "); } } return result; } }
标签:public strong log length imp blog emc main get
原文地址:http://www.cnblogs.com/wenhulu/p/6307371.html