标签：amp valueof try end append new exception dig uil
Reverse digits of an integer.
Example1: x = 123, return 321
Example2: x = -123, return -321
这道题要考虑反转之后overflow的问题，感觉我的写法很非主流啊。
public class Solution { public int reverse(int x) { String str = String.valueOf(x); StringBuilder s; if (x < 0) { s = new StringBuilder(str.substring(1, str.length())); s.append("-"); } else { s = new StringBuilder(str); } str = s.reverse().toString(); int newX = 0; try { newX = Integer.valueOf(str); } catch(Exception e) { } return newX; } }
还是用主流写法又写了一下
public class Solution { public int reverse(int x) { long newX = 0; while (x != 0) { int tmp = x % 10; newX = newX * 10 + tmp; x = x / 10; } if (newX > Integer.MAX_VALUE || newX < Integer.MIN_VALUE) { return 0; } return (int) newX; } }
标签：amp valueof try end append new exception dig uil
原文地址：http://www.cnblogs.com/aprilyang/p/6321821.html
