标签：length public 偶数 one else int 区别 sorted sort
Given an unsorted array nums, reorder it in-place such that nums[0] <= nums[1] >= nums[2] <= nums[3]....
For example, given nums = [3, 5, 2, 1, 6, 4], one possible answer is [1, 6, 2, 5, 3, 4].
此题需要把数组序号分成偶数和奇数来区别对待，代码如下：
public class Solution {
public void wiggleSort(int[] nums) {
for(int i=0;i<nums.length-1;i++){
if(i%2==0){
if(nums[i]>nums[i+1]) swap(nums,i,i+1);
}else{
if(nums[i]<nums[i+1]) swap(nums,i,i+1);
}
}
}
public void swap(int[] nums,int i,int j){
int temp = nums[i];
nums[i] = nums[j];
nums[j] = temp;
}
}
标签：length public 偶数 one else int 区别 sorted sort
原文地址：http://www.cnblogs.com/codeskiller/p/6360840.html
