标签:line code ber poster nes script blog span 区间修改
Time Limit: 2000MS | Memory Limit: 10000K | |
Total Submissions: 12265 | Accepted: 6484 |
Description
Input
Output
Sample Input
7 -15 0 5 10 -5 8 20 25 15 -4 24 14 0 -6 16 4 2 15 10 22 30 10 36 20 34 0 40 16
Sample Output
228
Source
#include <stdio.h> #include <algorithm> #define LEN 10000 using namespace std; struct Node { int left; int right; int count;//被覆盖次数 int line;//所包含的区间数量 int lbd;//左端点是否被覆盖 int rbd;//右端点是否被覆盖 int m;//测度,即覆盖的区间长度,如[2,8]就为6 }; struct ScanLine { int x;//横坐标 int y1;//扫描线的下端点 int y2;//扫描线的上端点 int flag;//若该扫描线属于矩形的左边的竖边, //如AB,则叫做入边,值为1,若属于矩形的右边的竖边,如CD,则叫做出边,值为0 }; struct Node node[LEN*4]; struct ScanLine scan[LEN]; int y[LEN]; void build(int l, int r, int i) { node[i].left = l; node[i].right = r; node[i].count = 0; node[i].m = 0; node[i].line = 0; if (r - l > 1) { int middle = (l + r)/2; build(l, middle, 2*i + 1); build(middle, r, 2*i + 2); } } //更新测度m void update_m(int i) { if (node[i].count > 0) node[i].m = y[node[i].right] - y[node[i].left]; else if (node[i].right - node[i].left == 1) node[i].m = 0; else { node[i].m = node[2*i + 1].m + node[2*i + 2].m; } } //更新line void update_line(int i) { if (node[i].count > 0) { node[i].lbd = 1; node[i].rbd = 1; node[i].line = 1; } else if (node[i].right - node[i].left == 1) { node[i].lbd = 0; node[i].rbd = 0; node[i].line = 0; } else { node[i].lbd = node[2*i + 1].lbd; node[i].rbd = node[2*i + 2].rbd; node[i].line = node[2*i + 1].line + node[2*i + 2].line - node[2*i + 1].rbd*node[2*i + 2].lbd; } } void insert(int l, int r, int i)//l和r分别是这条扫描线的下端点和上端点的纵坐标 //相当于区间修改 { //在这里要取离散化之前的原值进行比较 if (y[node[i].left] >= l && y[node[i].right] <= r) //如果这个区间内最下的点的纵坐标大于insert扫描线的上端点的纵坐标 //且这个区间内最上的点的纵坐标小于insert扫描线的下端点的纵坐标 (node[i].count)++;//这个区间包含于这条线段,一定覆盖了这个区间内的扫描线 else if (node[i].right - node[i].left == 1)return;//因为坐标都是整数 else { int middle = (node[i].left + node[i].right)/2; if (r <= y[middle])//这条扫描线完全包含于这个区间的中点到最下 insert(l, r, 2*i + 1); else if (l >= y[middle])//完全包含于这个区间的最上到中点 insert(l, r, 2*i + 2); else//穿过中点 { insert(l, y[middle], 2*i + 1); insert(y[middle], r, 2*i + 2); } } update_m(i); update_line(i); } void remove(int l, int r, int i) { //在这里要取离散化之前的原值进行比较 if (y[node[i].left] >= l && y[node[i].right] <= r) (node[i].count)--;//完全被包含就删去这条边 else if (node[i].right - node[i].left == 1) return; else { int middle = (node[i].left + node[i].right)/2; if (r <= y[middle]) remove(l, r, 2*i + 1); else if (l >= y[middle]) remove(l, r, 2*i + 2); else { remove(l, y[middle], 2*i + 1); remove(y[middle], r, 2*i + 2); } } update_m(i); update_line(i); } bool cmp(struct ScanLine line1, struct ScanLine line2) { if (line1.x == line2.x) return line1.flag > line2.flag; return (line1.x < line2.x); } int main() { int n; scanf("%d", &n);//输入有几个矩形 int x1, y1, x2, y2; int i = 0; while (n--) { scanf("%d %d %d %d", &x1, &y1, &x2, &y2);//(x1,y1)左下,(x2,y2)右上 scan[i].x = x1;//加扫描线 scan[i].y1 = y1; scan[i].y2 = y2; scan[i].flag = 1; y[i++] = y1;//y[]记录所有点的纵坐标 scan[i].x = x2; scan[i].y1 = y1; scan[i].y2 = y2; scan[i].flag = 0; y[i++] = y2; } sort(y, y + i);//所有纵坐标从下到上排序 sort(scan, scan + i, cmp);//所有扫描线从左到右排序 int unique_count = unique(y, y + i) - y;//y数组中不重复的个数 build(0, unique_count - 1, 0);//离散化,建立线段树 int perimeter = 0; int now_m = 0; int now_line = 0; for (int j = 0; j < i; j++)//枚举每条扫描线 { if (scan[j].flag)//如果是左边 insert(scan[j].y1, scan[j].y2, 0); else//如果是右边 remove(scan[j].y1, scan[j].y2, 0); if (j >= 1) perimeter += 2*now_line*(scan[j].x - scan[j-1].x); perimeter += abs(node[0].m - now_m); now_m = node[0].m; now_line = node[0].line; } printf("%d\n", perimeter); return 0; }
标签:line code ber poster nes script blog span 区间修改
原文地址:http://www.cnblogs.com/thmyl/p/6367092.html