UVa 242 邮票和信封（完全背包）

 1 #include<iostream> 
 2 #include<string>
 3 #include<cstring>
 4 #include<algorithm>
 5 using namespace std;
 6 
 7 const int maxn = 25;
 8 const int INF = 0x3f3f3f3f;
 9 
10 int s, n, m;
11 int a[maxn];
12 int dp[1005];
13 int ans[25];
14 
15 
16 int main()
17 {
18     //freopen("D:\\txt.txt", "r", stdin);
19     while (cin >> s && s)
20     {
21         int best = 0;         //最大连续邮资
22         int Max=INF;          //最大邮票的值
23         int number = INF;     //邮票数量
24         cin >> n;
25         for (int i = 0; i < n; i++)
26         {
27             cin >> a[0];
28             for (int j = 1; j <= a[0]; j++)
29                 cin >> a[j];
30             memset(dp, INF, sizeof(dp));
31             dp[0] = 0;
32             int now = 0;
33             for (int j = 1; j <= s*a[a[0]]+1; j++)
34             {
35                 for (int k = 1; k <= a[0] && j >= a[k]; k++)
36                     dp[j] = min(dp[j], dp[j - a[k]] + 1);
37                 if (dp[j]>s)
38                 {
39                     now = j - 1;
40                     break;
41                 }
42             }
43             if (now > best)   //此时的最大连续邮资大于了之前的
44             {
45                 best = now;
46                 number = a[0];
47                 Max = a[a[0]];
48                 memcpy(ans, a, sizeof(a));
49             }
50             else if (now == best)   //如果相等时
51             {
52                 if (a[0] < number)   //首先考虑邮票数量少的
53                 {
54                     number = a[0];
55                     Max = a[a[0]];
56                     memcpy(ans, a, sizeof(a));
57                 }
58                 else if (a[a[0]] < Max)   //如果邮票数量一样多，则优先考虑邮票最大的那张更小的
59                 {
60                     Max = a[a[0]];
61                     memcpy(ans, a, sizeof(a));
62                 }
63             }
64         }
65         printf("max coverage =%4d :", best);
66         for (int i = 1; i <= number; i++)printf("%3d", ans[i]);
67         puts("");
68     }
69     return 0;
70 }