标签:uva change while color case log include ace print
贪心的思想,如果S串是1而t串是0,只能够交换。除去相同的部分,如果上面的1比下面的1多,就无法变换成功,输出-1.
1 #include <bits/stdc++.h> 2 3 using namespace std; 4 const int maxn = 100+10; 5 int main() 6 { 7 char s[maxn],t[maxn]; 8 int x,i,j,kase = 0; 9 cin >> x; 10 while(x--) 11 { 12 int sum = 0,p = 0,cnt1 = 0,cnt2 = 0; 13 scanf("%s%s",s,t); 14 int len = strlen(s); 15 for(i=0; i<len; i++) 16 { 17 if(s[i]==‘?‘) 18 p++; 19 if(s[i] == ‘1‘&&t[i]==‘0‘) 20 cnt1++; 21 else if(t[i]==‘1‘&&s[i]!=‘1‘) 22 cnt2++; 23 } 24 if(cnt1>cnt2) 25 { 26 printf("Case %d: -1\n",++kase); 27 continue; 28 } 29 sum+=p; 30 int exchange = 0,other = 0; 31 for(i=0; i<len; i++) 32 { 33 if(s[i] == ‘1‘&&t[i]==‘0‘) 34 exchange++; 35 else if(s[i]==‘0‘&&t[i]==‘1‘) 36 other++; 37 } 38 sum += max(exchange,other); 39 printf("Case %d: %d\n",++kase,sum); 40 } 41 return 0; 42 }
标签:uva change while color case log include ace print
原文地址:http://www.cnblogs.com/HsiaoYeekwan/p/6390937.html