标签：blog os io for ar div amp log
Implement next permutation, which rearranges numbers into the lexicographically next greater permutation of numbers.
If such arrangement is not possible, it must rearrange it as the lowest possible order (ie, sorted in ascending order).
The replacement must be in-place, do not allocate extra memory.
Here are some examples. Inputs are in the left-hand column and its corresponding outputs are in the right-hand column.1,2,3 →
1,3,23,2,1 →
1,2,31,1,5 → 1,5,1
class Solution {
public:
void nextPermutation(vector<int> &num) {
// Note: The Solution object is instantiated only once and is reused by each test case.
next_permutation(num.begin(),num.end());
}
};
class Solution {
public:
void nextPermutation(vector<int> &num) {
vector<int>::iterator last = num.end() - 1;
if(last == num.begin())
return;
vector<int>::iterator prelast = last-1;
while(last != num.begin() && *prelast >= *last) {
prelast--;
last--;
}
if(last == num.begin()) {
sort(num.begin(),num.end());
return;
}
//from last to end() and get the minest
vector<int>::iterator minest = last;
for(vector<int>::iterator iter = last + 1;iter != num.end();++iter) {
if(*iter > *prelast && *iter <= *minest) {
minest = iter;
}
}
swap(*minest,*prelast);
reverse(last,num.end());
}
};
【Leetcode】Next Permutation,布布扣,bubuko.com
标签：blog os io for ar div amp log
原文地址：http://www.cnblogs.com/weixliu/p/3924356.html
