Paint House

标签：one   pre   ret   ted   imu   with   nim   span   mini   

There are a row of n houses, each house can be painted with one of the three colors: red, blue or green. The cost of painting each house with a certain color is different. You have to paint all the houses such that no two adjacent houses have the same color.

The cost of painting each house with a certain color is represented by a n x 3 cost matrix. For example, costs[0][0] is the cost of painting house 0 with color red; costs[1][2] is the cost of painting house 1 with color green, and so on... Find the minimum cost to paint all houses.

Note:
All costs are positive integers.

 1 public class Solution {
 2     public int minCost(int[][] costs) {
 3         int n = costs.length;
 4         if (n == 0 || costs[0].length == 0) return 0;
 5         
 6         for (int i = 1; i < n; i++) {
 7             costs[i][0] += Math.min(costs[i - 1][1], costs[i - 1][2]);
 8             costs[i][1] += Math.min(costs[i - 1][0], costs[i - 1][2]);
 9             costs[i][2] += Math.min(costs[i - 1][0], costs[i - 1][1]);
10         }
11         
12         return Math.min(costs[n - 1][0], Math.min(costs[n - 1][1], costs[n - 1][2]));
13     }
14 }

Paint House

标签：one   pre   ret   ted   imu   with   nim   span   mini   

原文地址：http://www.cnblogs.com/amazingzoe/p/6391372.html