标签:att div span tor void struct ret pre cstring
抽屉原理。
先统计最多有$sum$个船可以放,假设打了$sum-a$枪都没打中$a$个船中的任意一个,那么再打$1$枪必中。
#pragma comment(linker, "/STACK:1024000000,1024000000") #include<cstdio> #include<cstring> #include<cmath> #include<algorithm> #include<vector> #include<map> #include<set> #include<queue> #include<stack> #include<ctime> #include<iostream> using namespace std; typedef long long LL; const double pi=acos(-1.0); void File() { freopen("D:\\in.txt","r",stdin); freopen("D:\\out.txt","w",stdout); } template <class T> inline void read(T &x) { char c = getchar(); x = 0; while(!isdigit(c)) c = getchar(); while(isdigit(c)) { x = x * 10 + c - ‘0‘; c = getchar(); } } int n,a,b,k; char s[200010]; struct X { int L; int cnt; }t[200010]; int sz,cnt; int sum; int main() { cin>>n>>a>>b>>k; cin>>s; for(int i=0;s[i];) { if(s[i]==‘0‘) { int j; for(j=i;s[j];j++) { if(s[j]==‘0‘) continue; break; } j--; t[sz].L=i; t[sz].cnt=j-i+1; sz++; i=j+1; } else i++; } for(int i=0;i<sz;i++) sum=sum+t[i].cnt/b; int now=0; printf("%d\n",sum-a+1); for(int i=0;i<sz;i++) { for(int j=1;j<=t[i].cnt/b;j++) { printf("%d ",t[i].L+j*b); now++; if(now==sum-a+1) break; } if(now==sum-a+1) break; } return 0; }
标签:att div span tor void struct ret pre cstring
原文地址:http://www.cnblogs.com/zufezzt/p/6393311.html