数值的整数次方

 1 public class Solution {
 2     public double Power(double base, int exponent) {
 3         if(exponent>0){
 4             double dou = 1.0;
 5             for(int i = 0;i<exponent;i++){
 6                 dou = dou * base;
 7             }
 8             return dou;
 9         }
10         else if(exponent == 0){
11             return 1;
12         }
13         else {
14             double doub = 1.0;
15             for(int j = 0; j<-exponent;j++){
16                 doub = doub * base;
17             }
18             return 1/doub;
19         }
20   }
21 }