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Decode Ways

时间:2014-08-20 20:56:53      阅读:231      评论:0      收藏:0      [点我收藏+]

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A message containing letters from A-Z is being encoded to numbers using the following mapping:

‘A‘ -> 1
‘B‘ -> 2
...
‘Z‘ -> 26

Given an encoded message containing digits, determine the total number of ways to decode it.

For example,

Given encoded message "12", it could be decoded as "AB" (1 2) or "L" (12).

The number of ways decoding "12" is 2.

思路:使用DP求解该题。num[i]记录s的前i个字符的解码方案数。若s[i-1]不为‘0‘,则可由num[i-1]通过s[i-1]达到num[i];若s(i-2:i-1)(即s.substr(i-2,2))小于等于‘26’,则可由num[i-2]通过s(i-2:i-1)达到num[i]。

 1 class Solution {
 2 public:
 3     int numDecodings( string s ) {
 4         if( s.empty() || s[0] == 0 ) { return 0; }
 5         vector<int> num( s.length()+1, 0 );
 6         num[0] = 1; num[1] = 1;
 7         for( int i = 2; i <= (int)s.length(); ++i ) {
 8             if( s[i-1] != 0 ) { num[i] = num[i-1]; }
 9             if( s[i-2] == 1 || ( s[i-2] == 2 && s[i-1] <= 6 ) ) { num[i] += num[i-2]; }
10         }
11         return num.back();
12     }
13 };

 

Decode Ways,布布扣,bubuko.com

Decode Ways

标签:style   blog   color   使用   io   for   div   amp   

原文地址:http://www.cnblogs.com/moderate-fish/p/3925335.html

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