Consider all integer combinations of ab for 2 ≤ a ≤ 5 and 2 ≤ b ≤ 5:
22=4, 23=8, 24=16, 25=32
32=9, 33=27, 34=81, 35=243
42=16, 43=64, 44=256, 45=1024
52=25, 53=125, 54=625, 55=3125
If they are then placed in numerical order, with any repeats removed, we get the following sequence of 15 distinct terms:
4, 8, 9, 16, 25, 27, 32, 64, 81, 125, 243, 256, 625, 1024, 3125
How many distinct terms are in the sequence generated by ab for 2 ≤ a ≤ 100 and 2 ≤ b ≤ 100?
x=set() for a in range(2,101): for b in range(2,101): x.add(a**b) print len(x)
利用set 集合的无序,不重复性计算
projecteuler---->problem=29----Distinct powers,布布扣,bubuko.com
projecteuler---->problem=29----Distinct powers
原文地址:http://blog.csdn.net/q745401990/article/details/38724603