标签:fine splay can isp cte printf src exp b16
用并查集记录每个联通块的根节点,每个联通块建一棵线段树,合并时合并线段树就可以了。
代码:
1 #include<iostream> 2 #include<cstdio> 3 #include<cstring> 4 using namespace std; 5 #define N 100010 6 struct node{ 7 int l,r,x; 8 }c[N*20]; 9 int i,j,k,n,m,l,r,a[N],x,y,Rt[N],Num,b[N],f[N],f1,f2; 10 char s[2]; 11 inline int Find(int x){return x==f[x]?x:f[x]=Find(f[x]);} 12 inline void Update(int& Node,int l,int r,int x){ 13 if(!Node)Node=++Num; 14 if(l==r){c[Node].x++;return;} 15 int Mid=l+r>>1; 16 if(Mid<x)Update(c[Node].r,Mid+1,r,x);else Update(c[Node].l,l,Mid,x); 17 c[Node].x=c[c[Node].l].x+c[c[Node].r].x; 18 } 19 inline int Merge(int x,int y){ 20 if(!y)return x; 21 if(!x)return y; 22 c[x].l=Merge(c[x].l,c[y].l); 23 c[x].r=Merge(c[x].r,c[y].r); 24 c[x].x=c[c[x].l].x+c[c[x].r].x; 25 return x; 26 } 27 inline int Query(int Node,int l,int r,int R){ 28 if(l>R||!Node)return 0; 29 if(r<=R)return c[Node].x; 30 int Mid=l+r>>1; 31 return Query(c[Node].l,l,Mid,R)+Query(c[Node].r,Mid+1,r,R); 32 } 33 inline int Get_Ans(int x,int k){ 34 int l=1,r=n,Mid; 35 while(l<=r){ 36 Mid=l+r>>1; 37 if(Query(Rt[x],1,n,Mid)>=k)r=Mid-1;else l=Mid+1; 38 } 39 if(l>n)return -1;return b[l]; 40 } 41 int main() 42 { 43 scanf("%d%d",&n,&m); 44 for(i=1;i<=n;i++)scanf("%d",&a[i]),b[a[i]]=i,f[i]=i; 45 while(m--)scanf("%d%d",&x,&y),f[Find(x)]=Find(y); 46 for(i=1;i<=n;i++)Update(Rt[Find(i)],1,n,a[i]); 47 scanf("%d",&m); 48 while(m--){ 49 scanf("%s%d%d",s,&x,&y); 50 if(s[0]==‘Q‘)printf("%d\n",Get_Ans(Find(x),y));else{ 51 f1=Find(x);f2=Find(y); 52 if(f1!=f2){ 53 f[f1]=f2; 54 Rt[f2]=Merge(Rt[f1],Rt[f2]); 55 } 56 } 57 } 58 return 0; 59 }
bzoj2733 [ HNOI2012 ] -- 并查集+线段树合并
标签:fine splay can isp cte printf src exp b16
原文地址:http://www.cnblogs.com/gjghfd/p/6500465.html