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每日编程-20170308-2

时间:2017-03-08 21:29:45      阅读:197      评论:0      收藏:0      [点我收藏+]

标签:之间   cout   连续   blog   nbsp   for   大于   sum   else   

题目:给出两个自然数N和n,找到一组连续的自然数,其长度大于等于n,其和等于N。

输入:N(空格)n

输出:自然数列,每个数之间有空格,最后一个数后无空格 | 没有答案则输出:No answer

解答:

 1 #include <iostream>
 2 #include <vector>
 3 using std::cout; using std::endl; using std::cin;
 4 using std::vector;
 5 
 6 int main() {
 7 
 8     int N, n, sum = 0;  //sum为总和
 9     vector<int> answer;  //答案以vector形式保存,因为不确定会有多少
10     cin >> N >> n;  //输入参数
11     for (auto i = 1; i <= N/2; i++)  //遍历1到N/2,考虑到(N/2)+(N/2)+1 > N
12     {
13         for (auto j = i; sum < N ; j++)  //从i开始遍历,直到数列和不小于N
14         {
15             sum += j;
16             answer.push_back(j);
17         }
18         if (sum == N && ((answer.end() - answer.begin()) > n))  //如果sum等于N,并且answer长度大于n
19         {
20             for (auto beg = answer.begin(); beg != answer.end();beg++)  //输出answer
21             {
22                 cout << *beg;
23                 if (beg+1 != answer.end())
24                 {
25                     cout << " ";
26                 }
27             }
28             break;
29         }
30         else  //如果sum不等于N或者answer长度小于等于n
31         {
32             answer = {};  //清空答案,sum清零
33             sum = 0;
34         }
35     }
36     if (answer.begin() == answer.end())  //如果answer为空,没有答案
37     {
38         cout << "No answer" << endl;
39     }
40 }

 第二版

 1 #include <iostream>
 2 #include <vector>
 3 using std::cout; using std::endl; using std::cin;
 4 using std::vector;
 5 
 6 int main() {
 7 
 8     int N, n, sum = 0;
 9     vector<int> answer;
10     cin >> N >> n;
11     for (auto i = 1; i <= N/n; i++)  //数学改进,n(N/n) + n-1 > n
12     {
13         for (auto j = i; sum < N ; j++)
14         {
15             sum += j;
16             answer.push_back(j);
17         }
18         if (sum == N && (answer.size() > n))   //刚才脑残了,把size忘了
19         {
20             for (auto beg = answer.begin(); beg != answer.end();beg++)
21             {
22                 cout << *beg;
23                 if (beg+1 != answer.end())
24                 {
25                     cout << " ";
26                 }
27             }
28             break;
29         }
30         else
31         {
32             answer = {};
33             sum = 0;
34         }
35     }
36     if (answer.begin() == answer.end())
37     {
38         cout << "No answer" << endl;
39     }
40 }

 

每日编程-20170308-2

标签:之间   cout   连续   blog   nbsp   for   大于   sum   else   

原文地址:http://www.cnblogs.com/linhaowei0389/p/6522895.html

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