标签:tor cto amp turn return code back public sort
此问题可以分解为:当一个值确定,判断剩余的数中是否存在两个和为此数
需要检测完全
class Solution { public: vector<vector<int> > threeSum(vector<int>& nums) { sort(nums.begin(),nums.end()); vector <vector <int> > res; int target=0; for(auto iter = nums.begin();iter!=nums.end();iter++) { target= -*iter; auto front = iter+1; auto back = nums.end()-1; while(front < back) { int sum = *front + *back; if(sum < target) { front++; } else if(sum > target) { back--; } else { vector<int> one; one.push_back(-target); one.push_back(*front); one.push_back(*back); res.push_back(one); while(front < back && *front == one[1] )front++; while(front < back && *back == one[2] )back--; } } while( (iter+1) <nums.end()&&*(iter+1)==*(iter))iter++; } return res; } };
标签:tor cto amp turn return code back public sort
原文地址:http://www.cnblogs.com/wuya-study/p/6523407.html