Hello World!

2
11
7F 08 08 08 7F
38 54 54 54 18
00 41 7F 40 00
00 41 7F 40 00
38 44 44 44 38
00 00 00 00 00
3F 40 38 40 3F
38 44 44 44 38
7C 08 04 04 08
00 41 7F 40 00
38 44 44 48 7F
5
14 08 3E 08 14
04 02 01 02 04
40 40 40 40 40
04 02 01 02 04
14 08 3E 08 14

Case 1:

#   #        ##    ##               #   #              ##       #
#   #         #     #               #   #               #       #
#   #  ###    #     #    ###        #   #  ###  # ##    #    ## #
##### #   #   #     #   #   #       # # # #   # ##  #   #   #  ##
#   # #####   #     #   #   #       # # # #   # #       #   #   #
#   # #       #     #   #   #       # # # #   # #       #   #   #
#   #  ###   ###   ###   ###         # #   ###  #      ###   ####

Case 2:

        #           #        
  #    # #         # #    #  
# # # #   #       #   # # # #
 ###                     ### 
# # #                   # # #
  #                       #  
            #####            

题意：前面基本上都是废话，主要是让你自己看输入输出找规律。

题解：坑人的地方是这题输出的时候事实上是7行，而不是8行！！！因此PE了N次！

#include <stdio.h>
#define maxn 482

char map[8][maxn];
bool isPrint[8];

void getIsPrint(int n)
{
    for(int i = 0; i < 7; ++i){
        isPrint[i] = n & 1;
        n >>= 1;
    }
}

int main()
{
    //freopen("stdout.txt", "w", stdout);
    int t, n, arr[5], i, j, id, k, cas = 1;
    scanf("%d", &t);
    while(t--){
        scanf("%d", &n);
        for(i = id = 0; i < n; ++i){
            for(j = 0; j < 5; ++j, ++id){
                scanf("%X", arr + j);
                getIsPrint(arr[j]);
                for(k = 0; k < 7; ++k)
                    if(isPrint[k]) map[k][id] = '#';
                    else map[k][id] = ' ';
            }
            if(i != n - 1){
                for(k = 0; k < 7; ++k)
                    map[k][id] = ' ';
                ++id;
            }
        }
        printf("Case %d:\n\n", cas++);
        for(k = 0; k < 7; ++k){
            map[k][id] = '\0';
            printf("%s\n", map[k]);
        }
        printf("\n");
    }
    return 0;
}