Given a triangle, find the minimum path sum from top to bottom. Each step you may move to adjacent numbers on the row below.
For example, given the following triangle
[ [2], [3,4], [6,5,7], [4,1,8,3] ]
The minimum path sum from top to bottom is 11
(i.e., 2 + 3 + 5 + 1 =
11).
Note:
Bonus point if you are able to do this using only O(n) extra space, where n is the total number of rows in the triangle.
public class Solution { public int minimumTotal(List<List<Integer>> triangle) { int m=triangle.size(); int []f=new int[m+1]; for(int i=m-1;i>=0;i--){ for(int j=0;j<=i;j++){ f[j]=Math.min(f[j],f[j+1])+triangle.get(i).get(j); } } return f[0]; } }
原文地址:http://blog.csdn.net/dutsoft/article/details/38736603