标签：block ret play pat mil html generic mode att
ListView (带分页)
1.带分页效果的基础模板
1) view
from django.views.generic.list import ListView from employ.models import Company class CompanyListView(ListView): model = Company context_object_name = "companies" template_name = ‘company/company_list.html‘ paginate_by = 20
2) url
from django.conf.urls import url from . import views urlpatterns = [ url(r‘^$‘, views.CompanyListView.as_view(), name=‘company-list‘), ]
3) template
<table class="table table-striped"> <thead> <tr> <th>名称</th> <th>规模</th> </tr> </thead> <tbody> {% for company in companies %} <tr> <td>{{ company.name }}</td> <td>{{ company.scale }}</td> </tr> {% endfor %} </tbody> </table> {% if is_paginated %} <div class="pagination center-block"> <span>共{{ page_obj.paginator.num_pages }}页</span> <span id="paging" class="step-links" style="display: block;text-align: center"> {% if page_obj.has_previous %} <span><a href="?page={{ page_obj.previous_page_number }}">上一页</a></span> {% endif %} <span class="active">{{ page_obj.number }}</span> {% if page_obj.has_next %} <span><a href="?page={{ page_obj.next_page_number }}">下一页</a></span> {% endif %} </span> </div> {% endif %}
2.model < queryset < get_queryset()
这时候，页面上显示是model里的所有对象。如果我们希望这个object list排序后呈现呢？或者想要筛选部分呈现？这些又在哪定义呢？
很简单，这时候只要定义queryset或者重写get_queryset()方法就能搞定。
注意：model、queryset、get_queryset()至少要定义一个。而当三个都定义的时候，get_queryset()的效果强于queryset，而queryset的效果又强于model。
2.1 定义queryset
from django.views.generic.list import ListView from employ.models import Company class CompanyListView(ListView): context_object_name = "companies" template_name = ‘company/company_list.html‘ paginate_by = 20 queryset = Company.objects.all().order_by(‘-scale‘)
2.2 重写get_queryset()
from django.views.generic.list import ListView from employ.models import Company class CompanyListView(ListView): context_object_name = "companies" template_name = ‘company/company_list.html‘ paginate_by = 20
def get_queryset(self): companies = Company.objects.all().order_by(‘-scale‘) return companies
3.向template传递额外信息
以上，我们只向template中传递了关于某个Model里的所有对象。那么，我们有什么方法传递更多信息呢？
方法一：重写get_context_data()。如我想传递当前时间显示在template中：
view:
from django.views.generic.list import ListView from employ.models import Company from datetime import datetime class CompanyListView(ListView): context_object_name = "companies" template_name = ‘company/company_list.html‘ paginate_by = 20 queryset = Company.objects.all().order_by(‘-open_positions‘) def get_context_data(self, **kwargs): context = super(CompanyListView, self).get_context_data(**kwargs) context[‘now‘] = datetime.now() return context
template:
{{ now }}
方法二：在view中定义some_method()方法返回数据，在模版中使用{{ view.some_method }}。
注意：some_method(self)方法只能有一个self参数。
view：
from django.views.generic.list import ListView from employ.models import Company from datetime import datetime class CompanyListView(ListView): context_object_name = "companies" template_name = ‘company/company_list.html‘ paginate_by = 20 queryset = Company.objects.all().order_by(‘-open_positions‘) def now(self): return datetime.now()
template：
{{ view.now }}
django generic view - ListView
标签：block ret play pat mil html generic mode att
原文地址：http://www.cnblogs.com/rinka/p/django_generic_view_ListView.html
