标签:完全背包 log sort using std cout iostream poj ade
思路:
离散化+dp。
实现:
1 #include <iostream> 2 #include <cstdio> 3 #include <algorithm> 4 using namespace std; 5 6 const int INF = 0x3f3f3f3f; 7 8 int a[2005], b[2005], dp[2005][2005], n; 9 10 int solve() 11 { 12 for (int i = n - 1; i >= 0; i--) 13 { 14 dp[i][n - 1] = min(INF, dp[i + 1][n - 1]) + abs(a[i] - b[n - 1]); 15 for (int j = n - 2; j >= 0; j--) 16 { 17 dp[i][j] = min(INF, dp[i][j + 1] - abs(a[i] - b[j + 1])); 18 dp[i][j] = min(dp[i][j], dp[i + 1][j]); 19 dp[i][j] += abs(a[i] - b[j]); 20 } 21 } 22 int minn = INF; 23 for (int i = 0; i < n; i++) 24 { 25 minn = min(minn, dp[0][i]); 26 } 27 return minn; 28 } 29 int main() 30 { 31 cin >> n; 32 for (int i = 0; i < n; i++) 33 { 34 scanf("%d", &a[i]); 35 b[i] = a[i]; 36 } 37 int minn = INF; 38 sort(b, b + n); 39 minn = solve(); 40 cout << minn << endl; 41 return 0; 42 }
总结:
1.初步学会了离散化技巧。
2.初步学会了递推优化,对完全背包的理解更深入了。
标签:完全背包 log sort using std cout iostream poj ade
原文地址:http://www.cnblogs.com/wangyiming/p/6575781.html