标签:poj
Time Limit: 1000MS | Memory Limit: 65536K | |
Description
1 2 3 4 5 16 17 18 19 6 15 24 25 20 7 14 23 22 21 8 13 12 11 10 9
Input
Output
Sample Input
5 5 1 2 3 4 5 16 17 18 19 6 15 24 25 20 7 14 23 22 21 8 13 12 11 10 9
Sample Output
25
Source
#include<iostream> #include<cstdio> #include<cstring> const int offx[4]={1,0,-1, 0}; const int offy[4]={0,1, 0,-1},maxn=110; int r,c,dp[maxn][maxn],height[maxn][maxn]; int DP(int x,int y){ int ret=0; if(dp[x][y]!=-1) return dp[x][y]; for(int i=0;i<4;i++){ int newx=x+offx[i],newy=y+offy[i]; if(newx<0||newy<0||newx>=r||newy>=c) continue; if(height[x][y]<=height[newx][newy]) continue; if(DP(newx,newy)>ret) ret=DP(newx,newy); } return dp[x][y]=ret+1; } void solve(){ int ans=0; for(int i=0;i<r;i++){ for(int j=0;j<c;j++){ if(DP(i,j)>ans) ans=DP(i,j); } } printf("%d\n",ans); } int main(){ while(scanf("%d%d",&r,&c)!=EOF){ memset(dp,-1,sizeof(dp)); for(int i=0;i<r;i++){ for(int j=0;j<c;j++){ scanf("%d",&height[i][j]); } } solve(); } return 0; }
标签:poj
原文地址:http://blog.csdn.net/hush_lei/article/details/38755639