标签:leetcode
Given a m x n matrix, if an element is 0, set its entire row and column to 0. Do it in place.
原题链接:https://oj.leetcode.com/problems/set-matrix-zeroes/
题目:给定一个m * n 的矩阵,如果有一个元素是0,将其所在行和列设为0.
思路:先记录下是0 的元素的位置,再去置0.
public void setZeroes(int[][] matrix) { boolean firstRowZero = false,firstColumnZero = false; for(int i=0;i<matrix.length;i++){ if(matrix[i][0] ==0){ firstColumnZero = true; break; } } for(int i=0;i<matrix[0].length;i++){ if(matrix[0][i] ==0){ firstRowZero = true; break; } } for(int i=1;i<matrix.length;i++){ for(int j=1;j<matrix[0].length;j++){ if(matrix[i][j] ==0){ matrix[i][0]=0; matrix[0][j]=0; } } } for(int i=1;i<matrix.length;i++){ for(int j=1;j<matrix[0].length;j++){ if(matrix[i][0] ==0 || matrix[0][j]==0){ matrix[i][j]=0; } } } if(firstRowZero){ for(int i=0;i<matrix[0].length;i++) matrix[0][i]=0; } if(firstColumnZero){ for(int i=0;i<matrix.length;i++) matrix[i][0]=0; } }
标签:leetcode
原文地址:http://blog.csdn.net/laozhaokun/article/details/38777397