标签:blog signal val cout his output cal ios stream
Description
A number sequence is defined as follows:
f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7.
Given A, B, and n, you are to calculate the value of f(n).
Input
The input consists of multiple test cases. Each test case contains 3 integers A, B and n on a single line (1 <= A, B <= 1000, 1 <= n <= 100,000,000). Three zeros signal the end of input and this test case is not to be processed.
Output
For each test case, print the value of f(n) on a single line.
Sample Input
1 1 3
1 2 10
0 0 0
Sample Output
2
5
(a+b) mod c == (a mod c + b mod c) mod c
又因为任何数 mod c 只会有 0~c-1 这c种结果之一,所以(a mod c + b mod c) 总共有 c*c 种可能。即周期为 c*c。
斐波那契数列对一个数取模,其结果的数列为一个周期数列。
#include <iostream> using namespace std; int main(void) { int a, b, n; int s[50]; while(cin >> a >> b >> n && (a || b || n)) { s[0] = 1; s[1] = 1; for(int i = 2; i < 49; i++) { s[i] = (a*s[i-1]+b*s[i-2]) % 7; } cout << s[n%49-1] << endl; } return 0; }
标签:blog signal val cout his output cal ios stream
原文地址:http://www.cnblogs.com/limyel/p/6671347.html