标签:math ring algo strcpy -- queue getchar oid define
1 /* 2 POJ2166 Death to Binary? 3 http://poj.org/problem?id=2116 4 齐肯多夫定理 5 6 */ 7 #include <cstdio> 8 #include <algorithm> 9 #include <cstring> 10 #include <cmath> 11 #include <vector> 12 #include <queue> 13 #include <iostream> 14 #include <map> 15 #include <set> 16 //#define test 17 using namespace std; 18 const int Nmax=1e6+7; 19 char s[50],a[50],b[50],c[50],tmp[50],t[50]; 20 long long f[50]; 21 vector<long long> v; 22 vector<long long>::iterator it; 23 long long scan() 24 { 25 char c=getchar(); 26 while(c==‘ ‘||c==‘\n‘) 27 c=getchar(); 28 if(c==-1) 29 return -1; 30 int sz=0; 31 while(c>=‘0‘ && c<=‘1‘) 32 { 33 s[++sz]=c; 34 c=getchar(); 35 } 36 long long x=0LL; 37 for(int i=1;i<=sz;i++) 38 { 39 x+=1LL*(s[i]-‘0‘)*f[sz-i]; 40 } 41 return x; 42 } 43 int id(long long x) 44 { 45 int now=upper_bound(v.begin(),v.end(),x)-v.begin(); 46 if(now!=0) 47 now--; 48 return now; 49 } 50 char* get(long long x) 51 { 52 int sz=0; 53 for(int i=0;i<=40;i++) 54 tmp[i]=‘0‘; 55 //printf("\n"); 56 while(x>0) 57 { 58 //printf("x:%lld\n",x); 59 tmp[id(x)]=‘1‘; 60 sz=max(sz,id(x)); 61 //printf("%d ",id(x)); 62 //printf("%lld",f[id(x)]); 63 x-=f[id(x)]; 64 } 65 //printf("\n"); 66 //for(int i=0;i<=40;i++) 67 //printf("%c",tmp[i]); 68 //printf("\n"); 69 70 //printf("%s\n",tmp); 71 72 for(int i=sz;i>=0;i--) 73 t[sz-i]=tmp[i]; 74 t[sz+1]=‘\0‘; 75 return t; 76 } 77 void print() 78 { 79 int n=strlen(c); 80 int sum=n+2; 81 int an=strlen(a); 82 int bn=strlen(b); 83 for(int i=1;i<=sum-an;i++) 84 putchar(‘ ‘); 85 printf("%s\n",a); 86 putchar(‘+‘); 87 for(int i=1;i<=sum-bn-1;i++) 88 putchar(‘ ‘); 89 printf("%s\n",b); 90 putchar(‘ ‘); 91 putchar(‘ ‘); 92 for(int i=1;i<=n;i++) 93 putchar(‘-‘); 94 putchar(‘\n‘); 95 putchar(‘ ‘); 96 putchar(‘ ‘); 97 printf("%s\n\n",c); 98 } 99 int main() 100 { 101 #ifdef test 102 #endif 103 //freopen("poj2166.in","r",stdin); 104 f[0]=1LL; 105 f[1]=2LL; 106 for(int i=2;i<41;i++) 107 f[i]=f[i-1]+f[i-2]; 108 for(int i=0;i<=40;i++) 109 v.push_back(f[i]); 110 while(1) 111 { 112 long long x=scan(); 113 //printf("%lld\n",x); 114 if(x==-1) 115 break; 116 long long y=scan(); 117 if(y==-1) 118 break; 119 long long ans=x+y; 120 //long long ttt=40LL; 121 //while(ttt>0) 122 //{ 123 //printf("%d\n",id(ttt)); 124 //printf("%lld\n",f[id(ttt)]); 125 //ttt-=f[id(ttt)]; 126 //} 127 //strcpy(a,get(40LL)); 128 //printf("%s\n",a); 129 strcpy(a,get(x)); 130 strcpy(b,get(y)); 131 strcpy(c,get(ans)); 132 print(); 133 } 134 return 0; 135 }
标签:math ring algo strcpy -- queue getchar oid define
原文地址:http://www.cnblogs.com/BBBob/p/6698239.html